Please help find the value of sine.

Answers

Answer 1

Answer: Ok so all you have to do to find sine is divide the length of one side by another side. So the "Hypotenuse" is the long one, 12, by the "Opposite" is the shortest side, 8. 12 divided by 8 is 1.5 and that as a fraction is 3/2. So your answer is D. 3/2.

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Solve the equation x/4+3=19 and verify the solution
what is 2.1 rounded to the nearest tenth?

In which quadrant is the number -14 – 5i located on the complex plane? a.I b.II C.III D IV

Answers

I believe It’s c.III (quadrant 3)

Determine the quotient below

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$(18)/(7) / (9)/(6) = (18)/(7) * (6)/(9) = (12)/(7) \n$

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Answer:

12/7

Step-by-step explanation:

1. Convert to improper fraction:

2*7+4=18/7
1*6+3=9/6 (simplifies to 3/2)

2. Change sign and find reciprocal of second number

18/7*2/3

3. Multiply

18*2=36
7*3=21

4. Simplify

36 and 21 GCF = 3
Divide num and dem by 3
12/7 is final answer

Solve and graph the absolute value inequality: |2x + 4| > 14

Answers

$|2x+4| > 14\n\n2x+4 > 14\ \vee\ 2x+4 < -14\n\n2x > 14-4\ \vee\ 2x < -14-4\n\n2x > 10\ \vee\ 2x < -18\n\nx > 5\ \vee\ x < -9\n\nsee\ a\ picture\n\nx\in(-\infty;-9)\ \cup\ (5;\ \infty)$

|2x + 4| > 14
2x+ 4 = 14 2x + 4 = -14
x = 5 or x = - 9
2*5 = 10 +4 = 14 Yes
2*-9 = -18 + 4 = - 14 Yes
2x > 10 2x < - 18
X > 5
X < -9

Suppose the diameter of a paint can is 6.2483 inches. What is the width of four paint cans on a shelf, to the nearest hundredth of an inch? A. 24.99 inches
B. 25.00 inches
C. 31.25 inches
D. 24.96 inches

Answers

Given that diameter of a paint can is 6.2483.

And we are asked to find width of four paint cans on a shelf.

Since we can only place paint cans adjacent to each other on a shelf, Total width will be addition of diameters of four paint cans.

Hence width = 6.2483+6.2483+6.2483+6.2483

= 24.9932 ≈ 24.99 inches( rounded off to nearest hundredth of an inch)

Hence correct option is 'A'.

Solve. -1/8c=2
a. 4
b. –16
c. –4
d. 16

Answers

$(-1)/(8c) =2$
This requires that c ≠ 0 , meaning c≠0
$(-1)/(8c) =2$
Multiply by x to eliminate var in denominator
$( \not c*(-1))/( 8 \not c) =c*2$
$(-1)/(8) =c*2$
Common denominator is 8
$(\not 8(-1))/(\not 8) =8c*2$
$-1=8c*2$
$-1=16c$
$x=-16$
The answer is: b. -16

Solve the following system of equations using substitution.u = 6 + t
36 = 2t + u
A. t = 10, u = 16
B. t = 10, u = 4
C. t = 14, u = 20
D. t = 16, u = 22

Answers

It's A. If U=16, 6+10=16
and if you plug in the numbers for the second equation it's 36=2(10)+16

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