Answer:
its 87% I took the test, hope this helps!
Step-by-step explanation:
CE is contained on line m.
Ray BC is the same as ray CB.
Ray AD is the same as ray AC.
∠EAD is created from AE and DA.
∠ECB is created from CE and CB .
We need to look at a diagram with lines, rays and points, and see which statements are true.
The true ones are:
To find this, we need to analyze each statement.
1) "CB is contained on line n."
CB defines the ray that passes through points C and B, and we can see that neither of these points is on line n, thus this statement is false.
2) CE is contained on line m.
This is true, both points C and E are online m.
3) Ray BC is the same as ray CB.
False,ray BCis has the starting point at B, while ray CB has the starting point at C. In the diagram, the only graphed ray is CB (because it starts at point C).
4) Ray AD is the same as ray AC.
True, thus both of these rays start at the same point, and both D and C are collinear, thus we can see that the ray AD contains point C, and the ray AC contains the point D.
5)∠EAD is created from AE and DA.
∠EAD is the angle where point A is the vertex and AE and AD are the two rays that define the angle.
Note that in the statement we have DA instead of AD, which is different, so the statement is false.
6) ∠ECB is created from CE and CB
Similar to before, but now the two rays are correctly written, so this is true.
If you want to learn more, you can read:
Answer:
2.CE is contained on the line m.
4.Ray AD is the same as ray AC.
6.Angle ECB is created from CE and CB.
Step-by-step explanation:
We are given that a diagram .
We have to find which statement are true about the given diagram.
1.CB is contained on the line n.
CB is not contained on the line n because point C and B are not lying on the line n.
Therefore, it not true.
2.CE is contained on the line m.
CE is contained on the line m because point C and E are lying on the line m.
Therefore, it is true.
3.Ray BC is the same as ray CB.
A ray has one initial point and has no terminal point.It can extend to infinity .
Ray CB has initial point C and it extends from the point B.
But there is no BC ray.
Therefore, it is not true.
4.Ray AD is the same as ray AC.
AD is a ray but AC is also
AD and AC are same because both have initial point A and extend in the same direction.
5.Angle EAD is created from AE and DA.
It is not true because angle EAD is formed by ray AE and ray AD not ray DA.
6.Angle ECB is created from CE and CB.
It is true because angle ECB is formed by ray EC and ray BC.
Answer:
T=4B+10C
Step-by-step explanation:
for every bag there are 4 doughnuts
for every carton there are 10 doughnuts
You can solve the quadratic equation using the quadratic formula. For the system of three equations, use basic algebra according to the given condition. The equation involving sum of products can be solved by performing individual multiplications and then calculating the sum.
To help you understand and solve these mathematical equations, let's break them down. For the
quadratic equation
4.90t² + 20t +c = 0, you can use the quadratic formula to find the values of t. It's important to note here that the quadratic formula is [-b ± sqrt(b² - 4ac)] / (2a).
Also, given the system of three equations and three unknowns (Qd, Qs, and P), you can solve these using basic algebra. With Qd = Qs you can set the demand and supply equations equal to each other: 16 - 2P = 2 + 5P. You can then rearrange and solve for P.
Lastly, you have an equation where calculation of the sum of the products is involved: 1(.35) + 2(.20) + 3(.15) + 4(.15) + 5(.10) + 6(.05) = 2.6 years. This means that each number is multiplied by the corresponding percentage and then all results are added up.
#SPJ11
A.
(3, 1)
B.
(3, 0)
C.
(1, 3)
D.
(0, 6)
Answer:
4j^3 + 5j^2 + 7j - 1
Step-by-step explanation:
(8j^3 - 3j^2 + 5)-(4j^3+8j^2+7j-6)
Distribute the -1 in front of the (4j^3+8j^2+7j-6)
8j^3 - 3j^2 + 5 - 4j^3 + 8j^2 + 7j - 6
We can combine anything with the same exponent number that "j" is raised to
8j^3 - 4j^3 = 4j^3
-3j^2 + 8j^2 = 5j^2
7j is just 7j since there is nothing else with just j in it
5 - 6 = -1
Add these together
4j^3 + 5j^2 + 7j - 1 is our final answer