The area of a rectangular city park is 25/54 square miles. The length of the park is 5/9 mile. what is the width in miles of the park?

Answers

Answer 1

Answer: $(25)/(54)$ divided by $(5)/(9)$
= $(25)/(54)$ multiplied by $(9)/(5)$
= $(5)/(6)$ miles

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From the set {21, 37, 45}, use substitution to determine which value of x makes the inequality true.x - 8 > 29 45 none of these 37 21

Find a fraction in between 21/34 and 34/55

Answers

Answer:

2311/3740

Step-by-step explanation:

34 = 2×17

55 = 5×11

LCM = 2×5×11×17 = 1870

⁵⁵⁾21/34 = ²⁾1155/1870 = 2310/3740

³⁴⁾34/55 = ²⁾1156/1870 = 2312/3740

2310/3740 < 2311/3740 < 2312/3740

Answer:

A fraction between that is 2311/3740

Step-by-step explanation:

This is because the denominator is simplified into one number and the fraction is taken from there.

Chip drank a cup of coffee with 140 milligramsof caffeine. If the caffeine is eliminated from his
body at a rate of 9.5% per hour, how much
caffeine will be in his body from this cup of
coffee 6 hours from now?

Answers

Answer:

it should be 43 percent left

Step-by-step explanation:

Two landscapers must mow a rectangular lawn that measures 100 feet by 200 feet. Each wants to mow no more than half of the lawn. The first starts by mowing around the outside of the lawn. How wide a strip must the first landscaper mow on each of the four sides in order to mow no more than half of the lawn? The mower has a 24-inch cut. Approximate the required number of trips around the lawn.

Answers

The total area of the complete lawn is (100-ft x 200-ft) = 20,000 ft².
One half of the lawn is 10,000 ft². That's the limit that the first man
must be careful not to exceed, lest he blindly mow a couple of blades
more than his partner does, and become the laughing stock of the whole
company when the word gets around. 10,000 ft² ... no mas !

When you think about it ... massage it and roll it around in your
mind's eye, and then soon give up and make yourself a sketch ...
you realize that if he starts along the length of the field, then with
a 2-ft cut, the lengths of the strips he cuts will line up like this:

First lap:
   (200 - 0) = 200
   (100 - 2) = 98
   (200 - 2) = 198
   (100 - 4) = 96

Second lap:
   (200 - 4) = 196
   (100 - 6) = 94
   (200 - 6) = 194
   (100 - 8) = 92

Third lap:
   (200 - 8) = 192
   (100 - 10) = 90
   (200 - 10) = 190
   (100 - 12) = 88

These are the lengths of each strip. They're 2-ft wide, so the area
of each one is (2 x the length).

I expected to be able to see a pattern developing, but my brain cells
are too fatigued and I don't see it. So I'll just keep going for another
lap, then add up all the areas and see how close he is:

Fourth lap:
   (200 - 12) = 188
   (100 - 14) = 86
   (200 - 14) = 186
   (100 - 16) = 84

So far, after four laps around the yard, the 16 lengths add up to
2,272-ft, for a total area of 4,544-ft². If I kept this up, I'd need to do
at least four more laps ... probably more, because they're getting smaller
all the time, so each lap contributes less area than the last one did.

Hey ! Maybe that's the key to the approximate pattern !

Each lap around the yard mows a 2-ft strip along the length ... twice ...
and a 2-ft strip along the width ... twice. (Approximately.) So the area
that gets mowed around each lap is (2-ft) x (the perimeter of the rectangle),
(approximately), and then the NEXT lap is a rectangle with 4-ft less length
and 4-ft less width.

So now we have rectangles measuring

   (200 x 100), (196 x 96), (192 x 92), (188 x 88), (184 x 84) ... etc.

and the areas of their rectangular strips are
   1200-ft², 1168-ft², 1136-ft², 1104-ft², 1072-ft² ... etc.

==> I see that the areas are decreasing by 32-ft² each lap.
   So the next few laps are
   1040-ft², 1008-ft², 976-ft², 944-ft², 912-ft² ... etc.

How much area do we have now:

   After 9 laps,    Area =   9,648-ft²
   After 10 laps, Area = 10,560-ft².

And there you are ... Somewhere during the 10th lap, he'll need to
stop and call the company surveyor, to come out, measure up, walk
in front of the mower, and put down a yellow chalk-line exactly where
the total becomes 10,000-ft².

There must still be an easier way to do it. For now, however, I'll leave it
there, and go with my answer of: During the 10th lap.

Which expression is equivalent to 56 + 21?07(49 + 14)
8(7 + 21)
8(48 + 13)
07(8 + 3)

Answers

Answer:

07(8 + 3) is the right answer

The volume of a hemisphere is 144 pi. Find the radius and total surface area.

Answers

Formula of the Volume of a hemisphere:
V = $(2)/(3)$ $\pi$ r³
144 $\pi$ = $(2)/(3)$ $\pi$ r³
Multiply by 3 to cancel fraction in the right side
144 $\pi$ × 3 = 2 $\pi$ r³
432 $\pi$ = 2 $\pi$ r³
Divide by 2 $\pi$ on either sides to isolate r³
$(432 \pi )/(2 \pi )$ = $(2 \pi )/(2 \pi )$ r³
2 $\pi$ and $2 \pi$ cancel out
216 = r³
Take cube root to find the radius
$\sqrt[3]{216}$ = $\sqrt[3]{r^3}$
6 = r
Radius is 6 units

The formula of the surface area of a hemisphere is:
S.A = 2 $\pi$ r² + $\pi$ r²
= $2\pi$ (6)² + $\pi$ (6)²
=2 $\pi$ × 36 + 36 $\pi$
= 72 $\pi$ + 36 $\pi$
= 108 $\pi$ units² (in terms of $\pi$ )
≈ 339.12 units²

Surface area = 108 $\pi$ units

What is equal to the expression square root of 40/2

Answers

First you would simplify what's in the square root, to get root 20. If you want the exact number, and not the approximation, you would take out whatever squares are in that number (20=2*2*5) so your answer is 2root5.

However, if you want the approximation, simply plug it into your calculator and get 4.18154055.

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