how to solve 4n²-3n-7=0

Answers

Answer 1

Answer: $4n^2-3n-7=0\n \n a=4, \ \ b=-3 \ \ c=-7\n \n \Delta = b^(2)-4ac = (-3)^(2)-4*4* (-7)= 9+112=121$

$x_(1)=(-b-√(\Delta ))/(2a) =( 3-√( 121))/(2*4)=( 3-11)/(8)= (-8 )/( 8)=-1 \n \nx_(2)=(-b+√(\Delta ))/(2a) =( 3+√( 121))/(2*4)=( 3+11)/(8)= (14 )/( 8)= (7)/(4)=1(3)/(4)$

Answer 2

Answer: $4n^2-3n-7=0\n\n\underbrace{(2n)^2-2\cdot2n\cdot(3)/(4)+\left((3)/(4)\right)^2}_((*))-\left((3)/(4)\right)^2=7\n\n(2n-(3)/(4))^2-(9)/(16)=7\n\n(2n-(3)/(4))^2=7+(9)/(16)\n\n(2n-(3)/(4))^2=(112)/(16)+(9)/(16)\n\n(2n-(3)/(4))^2=(121)/(16)\to2n-(3)/(4)=\sqrt(121)/(16)\ \vee\ 2n-(3)/(4)=-\sqrt(121)/(16)$

$2n=(11)/(4)+(3)/(4)\ \vee\ 2n=-(11)/(4)+(3)/(4)\n\n2n=(14)/(4)\ \vee\ 2n=-(8)/(4)\n\n2n=(7)/(2)\ \vee\ 2n=-2\n\nn=(7)/(4)\ \vee\ n=-1$

$(a-b)^2=a^2-2ab+b^2$

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-x[-x(x-a) - (a-x)]
x = -2 & a = -5

answer and enjoy the points :D

Answers

Answer:59

Step-by-step explanation:

Gerard has $30 to spend on lunches this month. Lunch costs him $1.50 each day. After Gerard buys lunch for 8 days, which statement is true?Gerard has spent less than 12 of his lunch money.

Gerard has spent 12 of his lunch money.

Gerard has spent more than 12 of his lunch money.

Gerard has spent almost all of his lunch money.

Answers

Answer: The correct option is

(A) Gerard has spent less than $(1)/(2)$ of his lunch money.

Step-by-step explanation: Given that Gerard has $30 to spend on lunches this month that costs him $1.50 each day.

We are to find the correct statement after Gerard buys lunch for 8 days.

We have

Cost of Lunch for one day = $1.50.

So, cost of lunch for 8 days will be

$\$(1.50* 8)=\$12.$

That is, Gerard has spent $12 of his lunch money in 8 days.

Also, the total amount of money Gerard has for lunch = $30.

So, half of the lunch money will be

$(30)/(2)=\$15.$

Since, 12 < 15, so Gerard has spent less than $(1)/(2)$ of his lunch money.

Thus, option (A) is correct.

Gerard has spent less than 1/2 of his lunch money.

Assuming that $g(x) = (1)/(3) f(x) \: and \: h(x) = - g(x) + 4$
fill in the following table.

Answers

The value of the functions g(-6) is 6, g(0) is 5, g(7) is 8, h(-6) is 2, h(0) is 9 and h(7) is 12.

x -6 0 7

f(x) -18 15 24

g(x) 6 5 8

h(x) 2 9 12

g(-6) = 6 because g(x) = 1/3 f(x) and f(-6) = -18.

g(0) = 5 because g(x) = 1/3 f(x) and f(0) = 15.

g(7) = 8 because g(x) = 1/3 f(x) and f(7) = 24.

h(-6) = 2 because h(x) = -g(x) + 4 and g(-6) = 6.

h(0) = 9 because h(x) = -g(x) + 4 and g(0) = 5.

h(7) = 12 because h(x) = -g(x) + 4 and g(7) = 8.

Please note that these are just the values of g(x) and h(x) at the specific points given in the table. To find the values of g(x) and h(x) for other values of x, you can use the given formulas.

To learn more about functions here:

brainly.com/question/35114770

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Which transformations are needed to change the parent sine function to the sine function below?

Answers

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k is the vertical shift(shift up or down)

What is the first step of the following division problem?(8x^3 – x^2 + 6x + 7) ÷ (2x – 1)

A. Divide 8x^3 by 2x.
B. Divide 2x by 8x^3.
C. Divide 6x by 2x.
D. Divide 2x by 6x.

Answers

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