What is the combined version of the equations 5.2*10^6 and 2.47*10^8

Answer:To solve the system of equations using substitution, we'll start by solving one equation for one variable, and then substitute that expression into the other equation.

Let's solve the second equation, y = 3x - 7, for y:

y = 3x - 7 (Equation 2)

Now, we can substitute this expression for y in the first equation, 2x + y = 3:

2x + (3x - 7) = 3

Combining like terms, we have:

5x - 7 = 3

Adding 7 to both sides of the equation, we get:

5x = 10

Dividing both sides of the equation by 5, we have:

x = 2

Now that we have the value of x, we can substitute it back into one of the original equations to find the value of y. Let's use Equation 2:

y = 3x - 7

Substituting x = 2, we have:

y = 3(2) - 7

Simplifying the expression, we get:

y = 6 - 7

y = -1

Therefore, the solution to the system of equations is x = 2 and y = -1.

We can also check this solution by substituting the values of x and y back into both original equations to make sure they satisfy both equations.

A pooling equilibrium exists as long as the number of Type H customers in the market is relatively low.

True or False

A pooling equilibrium exists as long as the number of Type H customers in the market is relatively high.

True or False

Brainly Ginny character avatar

AI-generated answer

A pooling equilibrium exists when all customers, regardless of their type, are offered the same product or service. In a pooling equilibrium, the market does not differentiate between different customer types.

Given the statement "A pooling equilibrium exists as long as the number of Type H customers in the market is relatively low," we can analyze its truthfulness:

If the number of Type H customers in the market is relatively low, it means that there are fewer customers of Type H compared to other types. In this scenario, it is more likely that the market will offer a single product or service that caters to the majority of customers, including non-Type H customers. Therefore, it is true that a pooling equilibrium is more likely to exist when the number of Type H customers is relatively low.

On the other hand, if the number of Type H customers in the market is relatively high, it means that there is a significant presence of Type H customers. In this case, the market might be inclined to offer specialized products or services that specifically cater to the needs and preferences of Type H customers. This would result in a segmentation or differentiation of the market, which contradicts the concept of a pooling equilibrium. Therefore, it is false to say that a pooling equilibrium exists when the number of Type H customers is relatively high.

To summarize:

- A pooling equilibrium is more likely to exist when the number of Type H customers in the market is relatively low. (True)

- A pooling equilibrium is less likely to exist when the number of Type H customers in the market is relatively high. (False)

what is the combined version of the equations 5.2*10^6 and 2.47*10^8

Brainly Ginny character avatar

AI-generated answer

To find the combined version of the given equations 5.2*10^6 and 2.47*10^8, we need to add or subtract the numbers and keep the same power of 10.

The numbers in scientific notation have two parts: the coefficient and the power of 10. In this case, we have:

5.2 * 10^6 and 2.47 * 10^8

To combine them, we need to make sure that the powers of 10 are the same. We can do this by adjusting the coefficients.

First, let's adjust the coefficient of 5.2*10^6. We can do this by multiplying it by 10^2:

5.2 * 10^6 * 10^2 = 5.2 * 10^(6+2) = 5.2 * 10^8

Now that we have adjusted the coefficient of 5.2*10^6, we can combine it with 2.47*10^8:

5.2 * 10^8 + 2.47 * 10^8 = (5.2 + 2.47) * 10^8 = 7.67 * 10^8

Therefore, the combined version of the equations 5.2*10^6 and 2.47*10^8 is 7.67*10^8.