f(x)= -99.4x + 198.8
f(1) = -99.4*1 + 198.8 = 99.4
f(2) = -99.4*2 + 198.8 = 0
f(3) = -99.4*3 + 198.8 = -99.4
f(4) = -99.4*4 + 198.8 = -198.8
Answer:
Which is a recursive formula for the sequence 99.4, 0, –99.4, –198.8, where f(1) = 99.4?
The answer will be : f(n + 1) = f(n) – 99.4, n ≥ 1
b. f(x) = (x – 7) (x – i) (x – 5) (x + i)
c. f(x) = (x – (7 – i)) (x – (5 + i)) (x – (7 + i)) (x – (5 – i))
d. f(x) = (x + (7 – i)) (x + (5 + i)) (x + (7 + i)) (x + (5 – i))
The polynomial function with a leading coefficient of 1 and roots (7 + i) and (5 – i) with multiplicity 1 is f(x) = (x + 7) (x – i) (x + 5) (x + i).
The polynomial function with a leading coefficient of 1 and roots (7 + i) and (5 – i) with multiplicity 1 is option a. f(x) = (x + 7) (x – i) (x + 5) (x + i). To understand why this is the correct answer, we first need to know that complex roots always appear in conjugate pairs, which means that if a + bi is a root, then a - bi is also a root. The given roots are (7 + i) and (5 – i), so the conjugate pairs are (7 – i) and (5 + i).
Therefore, the correct polynomial is obtained by multiplying the factors (x – (7 + i)), (x – (7 – i)), (x – (5 + i)), and (x – (5 – i)). This gives us f(x) = (x + 7) (x – i) (x + 5) (x + i), which is option a.
#SPJ12
Select one:
a. cos 70°
b. cos 44°
c. sin 44°
d. sin 70°
Answer: The correct option is (c) sin 44°.
Step-by-step explanation: We are given to write the following expression as the sine, cosine or tangent of an angle :
We will be using the following trigonometric formula :
Therefore, we get
Thus, the required expression can be written in sine of an angle of measure 44°.
Option (c) is CORRECT.