The coordinate of point L' after translation is L'(6, -8)
Given the coordinates of JKLM as J(-7,-2), K(-4,-2), L(-2,-5) and M(-9,-5)
Using the translation rule
(x, y) → (x + 8, y − 3)
The coordinate of point L' after translaton will be;
L' = (-2+8, -5-3)
L' = (6, -8)
Hence the coordinate of point L' after translation is L'(6, -8)
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2) (log2)6/(log2)3
3) (log3)2/(log6)2
4) (log6)2/ (log3)2 ...?
The correct expression for log3 6 as a logarithm of base 2 is option 1) (log₂ 3) / (log₂ 6).
To express log₃ 6 as a logarithm of base 2, we can use the change of base formula. The change of base formula states that logb x = (logc x) / (logc b), where c is any positive value other than 1.
Applying the change of base formula to log3 6:
log₃ 6 = (log₂ 6) / (log₂ 3)
Therefore, the correct expression for log3 6 as a logarithm of base 2 is option 1) (log₂ 3) / (log₂ 6).
To calculate it properly, we need to find the decimal approximation of this expression:
Using the appropriate logarithmic functions, we have:
(log₂ 3) / (log₂ 6) ≈ 1.58496 / 2.58496 ≈ 0.6124
Thus, log₃ 6 as a logarithm of base 2 is approximately 0.6124.
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-7
-1
1
7
To find the coordinates of B, we use the formula for finding the midpoint of a line segment. By plugging in given values and arranging the equation, we get B(8, -3).
To find the coordinates of B, you'd use the formula for the midpoint of a line segment. The midpoint is calculated as follows - ((x1+x2)/2, (y1+y2)/2). Here, the coordinates of the midpoint M(7,-5) and A(6, -7) are given.
Plugging these in the formula:
7=(6 + x2)/2
-5=(-7+ y2)/2
By cross multiplying and arranging the equations, we can find the value of x2 and y2 - these will be the coordinates of point B.
Solving the equations gives B(8, -3) as a result.
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Answer:(8,-3)
Step-by-step explanation:
X2=8 Y2=-3