MATHEMATICS HIGH SCHOOL

Prove that:{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } \right) } }=1

Show your workings.

Answers

Answer 1
Answer: { \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { { 3 }^( 0 ) }{ \sin { \left( \frac { \pi }{ 2 } \right) } } \right) } } } \right) } }=1\n{ \left( { e }^{ \sqrt { { e }^{ \ln { \left( \frac { 1 }{ 1} \right) } } } } \right) }^{ \ln { \left( \sqrt { { e }^{ \ln { \left( \frac { 1 }{1 } \right) } } } \right) } }=1\n
{ \left( { e }^{ \sqrt { { e }^( \ln 1 ) } } \right) }^{ \ln { \left( \sqrt { { e }^( \ln 1 ) } \right) } }=1\n{ \left( { e }^( \sqrt 1 ) \right) }^{ \ln { \left( \sqrt 1 \right) } }=1\n{ \left( { e }^ 1 \right) }^( \ln 1 )=1\n e ^( \ln 1 )=1\n1=1

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Questions that are circled with work please

R=wp solve for p ...........

Answers

The required simplification for the variable p is p = R/w.

Given that,
To determine the simplification of the given expression R=wp for p.

What is simplification?

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
Given expression,
R=wp
dividing both sides by w
R / w = wp / w
Since on the right side, both the w on the numerator and in the denominator will be eliminated.
p = R / w

Thus, the required simplification for the variable p is p = R/w.

Learn more about simplification here: brainly.com/question/12501526

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R=wp\n\nwp=R\ \ \ \ |divide\ both\ sides\ by\ w\neq0\n\n\boxed{p=(R)/(w)}

A student has 174 cm of ribbon for making bows. Each bow is made with 20 cm of ribbon. The student wants to make as many bows as possible. How many bows can the student make? How many centimeters of ribbon will be left over?

Answers

Step-by-step explanation:

To find how many bows can be made take the 174 and divide it by 20

You get 8.7. The student can make 8 full bows. Now take 20 and times it by eight, this is how much ribbon in total the student used in bows. 160. Now 174-160. This makes 14.

The student can make 8 full bows with 14cm of ribbon left over.

Please help me with this question please is so hard

Answers

Answer:

1) $101,400

2) $27,000

Step-by-step explanation:

1) For this, we can first find how much she makes in a year from her salary alone:

$2,200×12= $26400.

Now, she also received a commission of 2.5%, so we can take this percentage from 3 million to find the total from commission:

3,000,000×0.025= $75,000

Adding these two gives us a total of $101400.

2) We can use the Simple Interest Formula to solve this (I= Prt). Plug in the values given to give us:

I= 5000(1.08)(5)

I= $27000

Prove that cos(a-b) - cos(a+b) = 2sina sinb

Answers

We know:
cos(a - b) = cos(a)cos(b) + sin(a)sin(b)
cos(a + b) = cos(a)cos(b) - sin(a)sin(b)

cos(a - b) - cos(a + b) = 2sin(a)sin(b)

L = cos(a)cos(b) + sin(a)sin(b) - (cos(a)cos(b) - sin(a)sin(b))

= cos(a)cos(b) + sin(a)sin(b) - cos(a)cos(b) + sin(a)sin(b)

= 2sin(a)sin(b) = R

Solve the inequality. 42 < –6d
A. d < –7
B. d < 36
C. d > –7
D. d < –48

Answers

42 < -6d

divide 6 by both sides,

7 < -d

(C) d > -7 is the answer.

A triangle has squares on its three sides as shown below what is the value of x

Answers

Answer:

5 cm

Step-by-step explanation:
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