MATHEMATICS HIGH SCHOOL

[OU.03]The table below shows the initial masses of four stars.Name of Star Star 1 Star 2 Star 3 Star 4
Initial mass of star (in Solar mass) 9 0.9 5 0.3

Which of these best shows the stars in the increasing order of the time for which they will stay on the main sequence?

Answers

Answer 1

Answer:

Answer: Star 1> Star 3 >Star 2> Star 4

Step-by-step explanation:

Since according to the given table ,

Mass of star 1 = 9 unit

Mass of star 2 = 0.9 unit

Mass of star 3 = 5 unit

Mass of star 4 = 0.3 unit.

Since mass is directly proportional to the time. ( E= m c^2)

Here, 9 unit > 5 unit > 0.9 unit > 0.3 unit ( order of masses)

Therefore sequence of the stars according to their increasing order of their time.

Star 1> Star 3 >Star 2> Star 4

Answer 2

Answer: Choices:
Star 1, Star 2, Star 3, Star 4
Star 1, Star 3, Star 2, Star 4
Star 4, Star 3, Star 2, Star 1
Star 4, Star 2, Star 3, Star 1

My answer would be: Star 4(0.3), Star 2(0.9), Star 3(5), Star 1(9)

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Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50a + 3.75b = 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold?

Answers

Given:
b = 82
\
Asked:
a = number of adult tickets sold = ?

Solution:
10.50(a) + 3.47(82) = 2071.50

solving for a:

a= [2071.5-3.47(82)]/10.50

a=168

FINAL ANSWER: There were 168 adult tickets sold.

Answer:

The correct answer would be , a = 168 tickets were sold

Step-by-step explanation:

Cost of adults ticket = $10.5

Cost of Students Ticket = %3.75

Sales Totals for opening night = $2071.5

Equation would be

10.5a + 3.75b = 2071.5

If 82 students attended the the play at that night, it means the value of b would be 82. Thus substituting the value in the above equation, we can find the value of a, which means how many adult tickets were sold.

10.5a + 3.75(82) = 2071.5

10.5a + 307.5 = 2071.5

10.5a = 2071.5-307.5

10.5a = 1764

a= 168 tickets were sold.

Need a quick answer for this homework

Answers

Answer:

clothes are expensive

Step-by-step explanation:

the hypothesis is at the beginning of the sentence followed by the conclusion

Plz help me with this...
Will give the brainliest
Urgent!!!

Answers

-1, 0, 1, 2... i believe those are the only integers

PLEASE HELP I WILL GVE BRAINLIEST

Answers

Answer:

-3y

Step-by-step explanation:

- $√(9)$ $\sqrt{y^(2) }$

--> -3 $\sqrt{y^(2) }$

--> -3y

I am confused on numbers 25 and 29, the instructions are at the top.

Answers

Pretty sure you already had something posted about this... in case you've lost it, or have questions:

#25 is fairly simple. Plug in -4 and 3 into the equation, and the extraneous root will be the one that does not work.
$√(12-(-4)) = √(16) = \frac{+}{}4$
Extraneous root in this case is positive four since +4≠-4
$√(12-3) = √(9) = \frac{+}{}3$
In this case it's negative 3, since -3≠3

#29 can be turned into a quadratic equation.
$x= √(2x+3)$
Square both sides to get
$x^(2)=2x+3$
Then bring the 2x+3 to the other side, setting the quadratic equal to zero.
$x^(2)-2x-3=0$
Factor to find that it's equivalent to
(x-3)(x+1)=0
Therefore x is equal to positive 3 and negative 1. Plug both back into the original equation. Whichever does not work is the extraneous root, and the answer is the one that does.
$x= √(2x+3)$
$3= √(2(3)+3)$
$3= √(9)$
Extraneous root would be negative 3.

$-1= √(2(-1)+3)$
$-1= √(1)$
Extraneous root would be positive 1.

Your answers are positive 3 and negative 1.
Extraneous roots are negative 3 and positive 1.

I need help on this question