Questions that are circled with work please
questions that are circled with work please - 1

Answers

Answer 1
Answer: Longer sides have longer angles. So the side length corresponds with the angle size.
 For example in 16 (that is the only one I can see properly), angle C is the largest. That means that the side facing it will be the largest. So side AB will be the largest, then BC and AC in that order because angle A is greater than angle B.
Hope this helps. 

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Algebra 1b radical expressions & data analysis1. Simplify 2/√5

A. 2/√5
B. √10
C. √10/5
D. 2√10/5 *** My answer

2. Simplify -11√112

A. -44√7
B. -176 √7
C. -27 √7
D. 4√7 *** My answer

3. Simplify 17√17 -9 √17

A. 8 *** My answer
B. 8√17
C. 26√17
D. 8√0

4. Simplify 6/ √3 + 2

A. 4/ √3
B. 12 - 6 √3 *** my answer
C. √3 - 2
D. 3

5. What is the domain of the function y = 3√6x + 42 ?

A. X≥0
B. X ≤7 *** my answer
C. X ≥ -6
D. X ≥ -7

6. What are the domain and range of the function y = 2 √3x + 4 - 5 ?

A. X ≥ -4/3 ; y ≥ -5 *** my answer
B. X ≥ 4/3 ; y ≥ -5
C. X ≤ -4/3 ; y ≤ -5
D. X ≥ -4/3 ; y ≥5

7. When will the dependent variable in the equation y = √x+4 - 3 equal or exceed 4 ?

A. X ≥ -0.17
B. X ≥ 45
C. X ≥ 48 *** my answer
D. X ≥ 53

8. Simplify the radical expression. Show all of the steps.

√363 - 3√27

Answers

1 none
2 a
3 b
4 none
5 d
6 a
7 b
√(363) - 3 √(27) = √(3 * 11 * 11) - 3 √(3*3*3) = 11√(3) - 9 √(3) = 2√(3)

Ax+b=3(x-a) solve for x

Answers

Ax + b = 3x -3a
Ax- 3x = -(3a+b)
x(A-3) = - (3a+b)
x = - (3a+b) / (A-3)

Apply the distributive property.
ax+b=3(x)+3(−a)

Multiply 3 by x to get 3x.
ax+b=3x+3(−a)

Move −1. 
ax+b=−1⋅3a 

Multiply −1 by 3 to get −3. 
ax+b=−3a 

Replace back in to larger expression. 
ax+b=3x−3a 

Since 3x contains the variable to solve for, move it to the left-hand side of the equation by subtracting 3x from both sides.
ax+b−3x=−3a

Factor out the GCF of x from each term in the polynomial.
x(a)+x(−3)=−b−3a

Factor out the GCF of x from ax−3x.
x(a−3)=−b−3a

Divide each term in the equation by (a−3).
x=−3a+b/a−3


Answer:
x=−3a+b/a−3

Write an expression that shows how to use the halving and doubling strategy to find 28 x 50

Answers

doubling strategy( 28 × 50 ) × 2 = 2800
halving strategy 2800/2 = 1400

What is the factored form of 5x+x^2=0

Answers

5x+x^2=0\n \nx(5+x)=0\n \nx=0 \ \vee \ 5+x=0 \n\n x=0 \ \vee \ x=-5


Jeremy got a haircut and paid 15% as a tip.A. what percent of the cost did jeremy pay the barber, including the tip:

B. what is the cost of the haircut

C. calculate the total cost of the haircut, including the tip

D.If you only wanted to know the tip amount, how would you change the process you used in part c to calculate the total cost

Answers

Answer:

Sure! Here are the answers:

A. Jeremy paid 100% + 15% = **115%** of the cost to the barber, including the tip.

B. Let's say the cost of the haircut is x dollars. Then, Jeremy paid a tip of 15% of x which is 0.15x dollars. Therefore, the cost of the haircut is x + 0.15x = **1.15x** dollars.

C. The total cost of the haircut, including the tip is 115% of the cost of the haircut. So, if the cost of the haircut is x dollars, then the total cost is 115% of x which is 1.15x dollars.

D. If you only wanted to know the tip amount, you would calculate 15% of the cost of the haircut which is 0.15 times x or **0.15x** dollars.

I hope this helps!

Step-by-step explanation:

Sam used 17 cans of paint to paint 6 walls. He used the same amount of paint on each wall. Which is the correct way to show how to find how many cans of paint he used for each wall.

Answers

Answer:

The number of cans of paint he used for each wall is 2(5)/(6) cans

Step-by-step explanation:

Here we are told that Sam used 17 cans of paint to paint 6 walls

The correct way to find out how many cans of paint he used to paint each wall is as follows

Number of walls 17 cans of paint can paint = 6 Walls, we therefore divide both side of the equation by 6 so that the number of walls painted will be 1 as follows

6 Walls = Number of walls 17 cans of paint can paint

6/6 Walls  = Number of walls 17/6 cans of paint can paint

∴ 1 Walls  = Number of walls 17/6 cans of paint can paint  or

∴ 1 Wall  = Number of walls 2(5)/(6) cans of paint can paint

Which gives;

Number of walls 2(5)/(6) cans of paint can paint = 1 Wall or

The number of cans of paint he used for each wall = 2(5)/(6) cans.