HELP!!!!!In a group of 15 children, 5 said they are an only child, 3 said they have 1 sibling only, 4 said they have exactly 2 siblings, and 3 said they have exactly 3 siblings.

What is the average number of siblings for this group? Enter your answer as a decimal, rounded to the nearest tenth,
_______

Answer:

A) Null Hypothesis; H0: μ = $41,500

Alternative hypothesis; H1: μ > $41,500

B) Reject H0 is t > 2.821433

C) t = 1.79

D) there is no sufficient evidence to support the claim that residents of Wilmington, Delaware have more income than the national average

Step-by-step explanation:

A) The hypotheses is given as;

Null Hypothesis; H0: μ = $41,500

Alternative hypothesis; H1: μ > $41,500

B) From online t-score calculator attached using significance level of 0.01 and DF = n - 1 = 10 - 1 = 9, we have;

t = 2.821433

Normally, when the absolute value of the t-value is greater than the critical value, we reject the null hypothesis. However, when the absolute value of the t-value is less than the critical value, we fail to reject the null hypothesis.

Thus, if t > 2.821433, we will reject the null hypothesis H0.

C) Formula for the test statistic is;

t = (x' - μ)/(s/√n)

We have, μ = 41500, x' = 47500, s = 10600, n = 10

t = (47500 - 41500)/(10600/√10)

t = 1.79

D) So, 1.79 is less than the t-critical value of 2.821433. Thus, we will fail to reject the null hypothesis and conclude that there is no sufficient evidence to support the claim that residents of Wilmington, Delaware have more income than the national average

Answer:

The probability that a randomly selected non-defective product is produced by machine B1 is 11.38%.

Step-by-step explanation:

Using Bayes' Theorem

P(A|B) =

where

P(B|A) is probability of event B given event A

P(B|a) is probability of event B not given event A  

and P(A), P(B), and P(a) are the probabilities of events A,B, and event A not happening respectively.

For this problem,

Let P(B1) = Probability of machine B1 = 0.3

P(B2) = Probability of machine B2 = 0.2

P(B3) = Probability of machine B3 = 0.5

Let P(D) = Probability of a defective product

P(N) = Probability of a Non-defective product

P(D|B1) be probability of a defective product produced by machine 1 = 0.3 x 0.01 = 0.003

P(D|B2) be probability of a defective product produced by machine 2 = 0.2 x 0.03 = 0.006

P(D|B3) be probability of a defective product produced by machine 3 = 0.5 x 0.02 = 0.010

Likewise,

P(N|B1) be probability of a non-defective product produced by machine 1 = 1 - P(D|B1) = 1 - 0.003 = 0.997

P(N|B2) be probability of a non-defective product produced by machine 2  = 1 - P(D|B2) = 1 - 0.006 = 0.994

P(N|B3) be probability of a non-defective product produced by machine 3 = 1 - P(D|B3) = 1 - 0.010 = 0.990

For the probability of a finished product produced by machine B1 given it's non-defective; represented by P(B1|N)

P(B1|N) = = = 0.1138

Hence the probability that a non-defective product is produced by machine B1 is 11.38%.

Answer:

6 miles

Step-by-step explanation:

Let's say the length of the sides of the square is x.

The area of a square is denoted by: A = x².

Here, we're given that twice the area of the square is 72, so we can write this is 2 times the area, which is 2 * x². Set this equal to 72 and solve:

2x² = 72

x² = 36

x = 6

Thus the answer is 6 miles.

Answer:

6 miles

Step-by-step explanation:

2A = 72

A = 72/2

A = 36

Area = s²

36 = s²

s = 6 miles

To find:

The x-values at the intersection of the graphs of two functions.

Solution:

Two functions are:

The functions are equal at the intersection. So,

The solutions of the above equation are the x-values of the intersection.

The solution to the above equation is:

It is given that x lies between -pi and pi. So, the value of n = 0 for the first solution and n = 1 for the second solution. Therefore,

Thus, options A and B are correct.

The combination is a way of selecting items from a collection where the order of selection does not matter.

The number of ways five students form a group for an​ activity is 6944.

What is a combination?

The combination is a way of selecting items from a collection where the order of selection does not matter.

The formula for combination is given:

We have,

Number of students = 32

Number of students in a group = 5

The number of ways five students form a group:

=

n = 32 and r = 5

=

= 32! / 5! (32 - 5)!

= 32! / 5! 27!

= 32 x 31 x 30 x 29 x 28 / 5 x 4 x 3 x 2

= 6944

Thus,

The number of ways five students form a group for an​ activity is 6944.

Learn more about combination here:

brainly.com/question/2970011

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yes it is reasonable that employment has a normal distribution for each gender