Apply this kinematics equation for the particle's vertical motion:
D = Vt + 0.5At²
D = vertical distance traveled, t = time, V = initial vertical velocity, A = vertical acceleration
Given values:
D = 49m
V = 34.3m/s
A = -9.81m/s²
Plug in and solve for t:
49 = 34.3t - 4.905t²
4.905t² - 34.3t + 49 = 0
Use the quadratic roots formula to find the values of t:
t ≈ 2, 5
The particle reaches a height of 49m at t = 2s & t = 5s
two or more electrical devices in a circuit can be connected by series connections or by parallel connections. When all the devices are connected using parallel connections, the circuit is referred to as a parallel circuit.
They're the circuits in which each end of one component is connected to one end of the other component.
If you have a picture of some circuits to pick the parallel ones from, it's a mystery to me why you haven't posted the picture too.
Conduction can occur between two objects that are very far apart.
Conduction decreases the movement of the atoms in both objects.
ball drops 45m under g=10m/s/s
45=1/2x10xt^2 ... application of kinematic equaion from rest
90/10=t^2
t=3
24.0 m in 3 secs => 8m/s no air resistance
The ball's initial speed is calculated using the principles of projectile motion. First, the time it takes for the ball to hit the ground is found using the vertical distance and acceleration due to gravity. the initial speed to be approximately 7.9 m/s.
The problem describes a case of projectile motion, a common topic in physics. Since the ball is thrown horizontally, the initial vertical velocity of the ball is zero. We're given that the horizontal distance covered is 24.0 m and the vertical distance is 45.0 m.
Because the horizontal and vertical motions are independent, we can use the equations of motion to solve the problem. First, we have to find the time it takes for the ball to hit the ground. Using the equation of motion
"y = 0.5*g*t²",
where y = 45 m is the vertical distance, g = 9.8 m/s² is the acceleration due to gravity, and t is the time in seconds. Solving for t gives us the square root of (2*y/g), which is approximately 3.03 seconds.
Second, we use this time to find the initial speed of the ball. The horizontal distance covered x = 24.0 m is equal to the product of the time it's been travelling and its initial horizontal speed (v = x/t). Using the time from the previous step, we can find the initial speed to be approximately 7.9 m/s.
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Visible light waves are the only electromagnetic waves we can see has the longest wavelength