Answer: An increase or decrease in energy!
Explanation: I just took the quiz, I got it wrong with the increase or decrease of pressure. This is the right answer nowww.
with a 4.63 N force at a 63.0° angle.
What is the force of friction on the
toy?
(Hint: You do NOT need to know the
coefficient of friction.)
The force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.
A force called friction prevents one solid object from rolling or sliding over another. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion.
Given parameters:
mass of the toy dog: M = 0.398 kg.
Applied force: F = 4.63 N.
Angle of application of force: θ = 63.0°
Hence, horizontal component of applied force = F cosθ
= 4.63 × cos63.0° N
= 2.10 N.
As the child drags a 0.398 kg toy dog across flat ground at constant speed, this component of applied force is nullified by force of friction.
Hence, the force of friction on the toy is 2.10 N and it acts opposite to the direction of its motion.
Learn more about friction here:
#SPJ2
Answer:
-2.1 N
Explanation:
I'm not sure of the numbers sense I dont have a calculator right now. The formula is 1/2*M*V^2.
The angular velocity of a clocks second hand, its minute hand, and its hour hand are 0.1047rad/s, 1.745 × 10⁻³rad/s and 1.454 × 10⁻⁴rad/s respectively.
Time period for second hand;
Time period for minute hand;
Time period for hour hand;
Now, we use the relation between angular speed and time period:
Where ω is the angular velocity and T is the time period in seconds.
For Second hand
For Minute hand
For Hour hand
Therefore, the angular velocity of a clocks second hand, its minute hand, and its hour hand are 0.1047rad/s, 1.745 × 10⁻³rad/s and 1.454 × 10⁻⁴rad/s respectively.
Learn more: brainly.com/question/8711708
Second hand:
1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec
Minute hand:
1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec
Hour hand:
1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec
As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.