The expected value of the rate of return is 23.5%
It is a branch of mathematics that deals with the occurrence of a random event.
Given is a table which gives the probabilitydistribution of the annual rate of return on the stock of MNP Company, Inc. We have to find out the expected value of the rate of return
Let X be the return and p probability
Then
X 15% 20% 30% 35% Total
p 0.2 0.4 0.3 0.1 1
x(p) 3 8 9 3.5 23.5
Hence Expected rate of return
E(x)= 23.5%
Hence, the expected value of the rate of return is 23.5%
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Answer:
A library contains only paperback and hardback books. If the ratio of paperback books to the total number of books is 3 to 5, the true statement is:
The ratio of paperback books to hardback books is 3 to 2.
Step-by-step explanation:
The number of books in the library = 5
The number of paperback books in the library = 3
Therefore, the number of hardback books in the library = 2 (5 - 3)
Then, the relationship between the paperback books and the hardback books in the library can be expressed as a ratio of 3:2. This still gives the sum of the ratios as 5, which is the total number of books in the library, including paperback and hardback books.
The correct statement is that the ratio of paperback to hardback books is 3:2. The ratios provided do not indicate the exact quantity of books in the library.
The ratio of paperbacks to the total number of books is 3:5. This means that for every 5 books, 3 are paperbacks and therefore, the remaining 2 must be hardbacks. Hence the ratio of paperback to hardback books is actually 3:2, not 2:3.
Note that the ratios given do not indicate the exact number of books. Therefore, we cannot confidently say that there are exactly 2 paperback books or exactly 8 hardback books in the library.
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The solution consists of all of the true intervals is −4 < x < −1 x > 1.
−4<x<−1 or x>1
Inequality Form: −4<x<−1 or x>1
Interval Notation: (−4,−1) ∪ (1,∞)
x^3 + 4x^2 > x + 4
Subtract x from both sides of the inequality.
x^3 + 4x^2 − x > 4
Convert the inequality to an equation.
x^3 + 4x^2 − x = 4
Move 4 to the left side of the equation by subtracting it from both sides.
x^3 + 4x^2>x+4
2 − x − 4 = 0
Factor the left side of the equation
(x + 4)(x + 1)(x − 1) = 0
If any individual factor on the left side of the equation is equal to, the entire expression will be equal to 0
x + 4 = 0
x + 1 = 0
x − 1 = 0
Set x + 4 equal to 0 and solve for x
x = −4
Set x + 1 equal to 0 and solve for x
Inequality is the difference in social status, wealth, or opportunity between people or groups. People are concerned about social inequality.
x = −1
Set x + -1 equal to 0 and solve for x
x = 1
The final solution is all the values that make (x + 4)(x + 1)(x − 1) = 0 true
x = −4, −1, 1
Use each root to create test intervals.
x < −4
−4 < x < −1
−1 < x < 1
x > 1
Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the
inequality.
x < −4 ←False
−4 < x < −1 ←True
−1 < x < 1 ←False
x > 1 ←True
The solution consists of all of the true intervals.
−4 < x < −1 x > 1
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Answer:
4.1 calls
Step-by-step explanation:
The number of calls (c) that Roger expects to get as a function of how many inches of snow fall (s), is described by the following linear model:
Therefore, when s = 4.7 inches, the number of service calls that Roger expects is:
Rounding to the nearest tenth, Roger will get about 4.1 calls.
Given that:
Length of a rope = 224 cm
Rope is cut so that one part is 3/4 of the other.
Solution:
Let one part of a rope be x cm.
So other part of the rope is .
Total length
Now,
Multiply both sides by 4.
Divide both sides by 7.
The value of one part 128 cm.
Second part
Therefore, the length of shorter rope is 96 cm and the length of longer rope is 128 cm.
The planes ABFE and EFGH intersected by line EF.
A prism is a polyhedron in geometry made up of an n-sidedpolygon basis, a second base that is a rigidly translated copy of the first base, and n additional faces that must all be parallelograms and connect the corresponding sides of the two bases.
We have cuboidal prism which have faces ABFE and EFGH.
To find the point for intersecting we have to find a point or line which is common in both planes.
Here the point E and F are common.
But the plane EF is also common
Thus, the intersecting line is line EF.
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Answer:
Line EF
Step-by-step explanation:
Planes intersect at lines