Changes in output are evenly spaced for evenly spaced changes in input, so the rule is linear. Changes in output are 1 for changes in input of 3, so the rule involves a factor of 1/3. One possible rule is
... output = (1/3)·input + 3
If y and x are used to represent output and input, respectively, this is
... y = (1/3)x + 3
Answer:
b. Keep the sample size the same and decrease the confidence level.
Step-by-step explanation:
We first have to find the critical value of z, which depends of the confidence level.
90% confidence level
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
99% confidence level
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
The width of the interval is:
In which is the standard deviation of the population and n is the size of the sample.
So, as z increses, so does the width. If z decreases, the width decreases. Lower confidence levels have lower values of z.
As n increases, the width decreses.
What will result in a reduced interval width?
b. Keep the sample size the same and decrease the confidence level.
Use the best fit line to estimate the distance for a trip that takes 20 minutes.
Enter your response in the box. Give the answer to the tenths place.
miles
Answer:
The anwser is 10.4
Step-by-step explanation:
0.5(20)+0.4
Help
Answer:
exact form: -28/8
decimal form: -3.625
mixed number form: -3 5/8
Answer:
x = -3.625
Step-by-step explanation:
Answer:
0.4 ; 0.6125
Step-by-step explanation:
Given the following :
Bag 1 : 75 red ; 25 blue
Bag 2: 60 red ; 40 blue
Bag 3: 45 red ; 55 blue
Probability = (required outcome / Total possible outcomes)
A) since the probability of choosing each bag is equal :
BAG A:
P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100
HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300
BAG B:
P(choosing bag B) = 1/3 ;
P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100
HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300
BAG C:
P(choosing bag C) = 1/3
P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100
HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300
= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4
2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?
BAG A:
P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100
HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375
BAG B:
P(choosing bag B) = (1-0.5) / 2 = 0.25 ;
P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100
HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1
BAG C:
P(choosing bag C) = (1 - (0.5+0.25)) = 0.25
P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100
HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375
= 0.1375 + 0.1 + 0.375 = 0.6125
Answer:
0.1
Step-by-step explanation:
hope this helps