MATHEMATICS COLLEGE

Please answer question 10 and 11 please

Answers

Answer 1

Answer:

Answer:

d7-dx=(20x|x-3|+40)x x-3 (|x-3+2)x| x-3|

Step-by-step explanation:

Hope this helps :D

Related Questions

Mr. Gordon has 13 girls and 14 boys in his fourth period algebra class. One person is chosen at random.What is the probability that the person chosen is a boy?A. 1/14 B. 1/27C. 13/14D. 13/27E. 14/27
Please answer sorry for bad photo
Two sides of a triangle measure 10cm and 15cm. which measure is possible for the third side
) of basketball players has a bell shaped distribution with mean 72.5 inches and standard deviation 3.25 inches. A height of 79 inches is at what percentile?
Explain how you know 437,160 is greater than 43,716

Please help me in this! you get 30 points!

Answers

Answer:

y=3x-2

Step-by-step explanation:

You can verify it's not D because the y-intercept is at -2.

You can verify it's not A because that would mean the x-intercept is 2 despite it appearing to be closer to one.

You can verify it's not B because that would mean the x-intercept is 1.5

It’s C. If I’m wrong sorry

Simplify the expression by removing symbols of grouping and combining like terms.3(r − 4s) − 5(3r − 5s)

Answers

Step-by-step explanation:

the answer is -12r+13s

if u need the explanation I gotchuu just lemme know or need work shown

hope it helps<33

You want to create an 80% confidence interval for the average age of people who attend U of O football games. You take a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years. Find the value of t* for this confidence interval. Do not round your answer. Write your answer in decimal form, not as a fraction or percent.

Answers

Answer:

80% confidence interval for the average age of people who attend U of O football games is [42.795 , 44.604].

Step-by-step explanation:

We are given that a sample of 100 attendees and find the average age to be 43.7 years old with a standard deviation of 7 years.

So, the pivotal quantity for 80% confidence interval for the population average start up cost is given by;

P.Q. = $(\bar X - \mu)/((s)/(√(n) ) )$ ~ $t_n_-_1$

where, $\mu$ = sample average age = 43.7 years old

$\sigma$ = sample standard deviation = 7 years

n = sample of attendees = 100

$\mu$ = population average age of people

So, 80% confidence interval for the average age of people, $\mu$ is ;

P(-1.2915 < $t_9_9$ < 1.2915) = 0.80

P(-1.2915 < $(\bar X - \mu)/((s)/(√(n) ) )$ < 1.2915) = 0.80

P( $-1.2915 * {(s)/(√(n) )$ < ${\bar X - \mu}$ < $1.2915 * {(s)/(√(n) )$ ) = 0.80

P( $\bar X -1.2915 * {(s)/(√(n) )$ < $\mu$ < $\bar X +1.2915 * {(s)/(√(n) )$ ) = 0.80

80% confidence interval for $\mu$ = [ $\bar X -1.2915 * {(s)/(√(n) )$ , $\bar X +1.2915 * {(s)/(√(n) )$ ]

= [ $43.7 -1.2915 * {(7)/(√(100) )$ , $43.7 +1.2915 * {(7)/(√(100) )$ ]

= [42.795 , 44.604]

Therefore, 80% confidence interval for the population average age of people who attend U of O football games is [42.795 , 44.604].

A class has 30 people at the beginning of the school term but now has five pupils what is the percent of increase

Answers

17 percent increase 5/30

What is the factors for 14 and 6

Answers

Answer:

14= 1, 2, 7, 14

6= 1, 2, 3, 6

A tank contains 22 gallons of water when all of a sudden the water begins draining at a constant rate of 2 gallons per hour. Let t represent the number of hours since the water begun draining and let v represent the volume of water in the tank. Write a formula that expresses y in terms of t .

Answers

Answer:

V= 22-2t

Step-by-step explanation:

I guess the alphabet should be v instead of y. So I am working using v

The rate at which water is draining from the tank is 2gallons/hour. This is the rate of water removal from the tank. So after an hour, 2 × 1= 2 gallons would have drained. After 5 hours, 2×5 =10 gallons would have drained

Therefore to obtain the amount of water in gallons that have been removed from the tank, you will multiply the rate by the time in hours after which the draining started.

Amount (gallons) =2×t

The amount of water remaining in the tank will be obtained by subtracting the amount of water drained after some hour (2×t) from the initial amount of water in the tank (22)

Therefore, the amount of water present in the tank (v)= 22-2t or 2(11-t) gallons

Final answer:

The formula to express volume of the water v in terms of time t is v = 22 - 2t, where 22 is the initial volume and 2t represents the rate at which the water is draining.

Explanation:

This problem is a mathematical representation of a real-world scenario using a linear equation. The volume of water v in the tank can be represented in terms of time t through the equation v = 22 - 2t. This equation illustrates the initial volume of water in the tank (22 gallons) and accounts for the constant rate at which the water is draining (2 gallons per hour).

When time t = 0 (meaning no time has passed since the water started draining), the volume of water v = 22 (the initial volume). As time increases, the volume gradually decreases at a rate of 2 gallons per hour, represented by the term -2t.

Learn more about Linear Equation here:

brainly.com/question/32634451

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