Explain how you know 437,160 is greater than 43,716

Answers

Answer 1
Answer: 437160 has more numbers than 43716
Answer 2
Answer:

Answer:

Because 437,160 is greater than 43,716

:)

Step-by-step explanation:

It has more numbers and on the number line, 437,160 is greater than 43,716

Think about it this way:

Suppose a company has a profit of $437,160 this spring.

And another one has $43,716 this spring.

Now, the question is:

Which company has a larger profit?

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Answers

One way to solve the function is to choose any 2 points on either of the 2 graphs. Then compare the 2 points and see what difference needed to have occurred to give the point on the f(x) graph.

Look if the change is made to the x and or the y coordinates. Knowing this, either place the change in brackets for the x values or simply outside for the y values.

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In a city known for many tech start-ups, 311 of 800 randomly selected college graduates with outstanding student loans currently owe more than $50,000. In another city known for biotech firms, 334 of 800 randomly selected college graduates with outstanding student loans currently owe more than $50,000. Perform a two-proportion hypothesis test to determine whether there is a difference in the proportions of college graduates with outstanding student loans who currently owe more than $50,000 in these two cities. Use α=0.05. Assume that the samples are random and independent. Let the first city correspond to sample 1 and the second city correspond to sample 2. For this test: H0:p1=p2; Ha:p1≠p2, which is a two-tailed test. The test results are: z≈−1.17 , p-value is approximately 0.242

Answers

Answer:

Null hypothesis:p_(1) - p_(2)=0  

Alternative hypothesis:p_(1) - p_(2) \neq 0  

z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)((1)/(800)+(1)/(800))}}=-1.182    

p_v =2*P(Z<-1.182)=0.2372  

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.  

Step-by-step explanation:

1) Data given and notation  

X_(1)=311 represent the number college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

X_(2)=334 represent the number college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

n_(1)=800 sample 1

n_(2)=800 sample 2

p_(1)=(311)/(800)=0.389 represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 (tech start-ups)

p_(2)=(334)/(800)=0.418 represent the proportion of college graduates with outstanding student loans currently owe more than $50,000 ( biotech firms)

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if is there is a difference in the two proportions, the system of hypothesis would be:  

Null hypothesis:p_(1) - p_(2)=0  

Alternative hypothesis:p_(1) - p_(2) \neq 0  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_(1)-p_(2)}{\sqrt{\hat p (1-\hat p)((1)/(n_(1))+(1)/(n_(2)))}}   (1)  

Where \hat p=(X_(1)+X_(2))/(n_(1)+n_(2))=(311+334)/(800+800)=0.403  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.389-0.418}{\sqrt{0.403(1-0.403)((1)/(800)+(1)/(800))}}=-1.182    

4) Statistical decision

Since is a two sided test the p value would be:  

p_v =2*P(Z<-1.182)=0.2372  

Comparing the p value with the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that we don't have significant difference between the two proportions.  

6.Write the equation in slope-intercept form for the line that passes through the given pointand is perpendicular to the given equation.5x + 3y = -21 and passes through (-5, 1)

Answers

Let us first solve for the slope (m) of the perpendicular line.

\text{ 5x + 3y = -21}\text{ 3y = -5x - 21}\text{ y =}\frac{-5x\text{ -21}}{3}\text{ y = -}(5)/(3)x-7

The slope of the perpendicular line is -5/3.

Thus, for the slope of the line, we get,

\text{ m}_(\perp)\text{ = }(-5)/(3)\text{ m = }(3)/(5)

Let us solve for the value of b with the given value of slope (m) = 3/5 and (x,y) = (-5,1).

\text{ y = mx + b}1\text{ = (}(3)/(5))(-5)+b1\text{ = -1 + b ; b = 1 + 1 = }2

Let's now make the equation of the line using Slope-Intercept Form,

Given, m = 3/5 and b = 2

\text{ y = mx+b}\text{ y = (}(3)/(5))x\text{ + 2}

\text{ y = }(3)/(5)x\text{ +2}

Jacqueline buys 2 fourths yard of green ribbon and 1 fourths yard of pink ribbon. How many yards of ribbon does she buy?

Answers

Answer:

3/4

Step-by-step explanation:

What is the probability of first drawing a red card, then a face card, and then a black card? Do not round your intermediate computations. Round your final answer to four decimal places.

Answers

Answer:

 [ 26 / 425 ] ≈ 0.0612

Step-by-step explanation:

Solution:-

- First we will describe the standard deck of 52 cards in terms of black, red and face cards found in a standard deck

- Following is a table of distribution of colored and face card found in a standard deck:

                 Type                   Number of cards

                 1 - 10                                40

                 Black                               26

                 Red                                 26

                 Face                                12

- The numerical cards from digit ( 1 to 10 ) are found in all 4 suits ( Clubs, Diamonds, Spades, and Hearts ). Hence, 10 x 4 = 40

- The entire deck is split in two colors ( Red and Black ) equally. So, the number of Black and Red cards are = 52 / 2 = 26 cards.

- The face cards are of three types ( King, Queen and Jack ). These three face cards are found in each of the 4 suits. Hence, Total number of face cards are = 4 * 3 = 12

- We will now consider the probabilities asscociated with each type. We will define 3 events and write down their proability as expressed:

Event ( A ): First draw is a red card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 red card in a standard deck of 52 cards. Hence,

            p ( A ) = [ Number of red cards ] / [ Total cards in a deck ]

            p ( A ) = [ 26 ] / [ 52 ]

            p ( A ) = 1 / 2

- After we make the first draw of a red card. Our deck distribution is changed to Number of Red cards remaining = 25 and total deck now has 51 cards remaining.

- We will define the next event as:

Event ( B ): The second draw is a face card.

- The probability of this event can be determined with the help of the table given above. There are a total of 12 face cards in a standard deck of 52 cards which is now down to 51 cards. Hence,

            p ( B ) = [ Number of face cards ] / [ Total cards in a deck ]

            p ( B ) = [ 12 ] / [ 51 ]

            p ( B ) = 4 / 17

- After we make the first draw of a face card. Our deck distribution is changed to Number of Face cards remaining = 11 and total deck now has 50 cards remaining.

- We will define the next event as:

Event ( C ): The third draw is a black card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 black cards in the deck. The total number of cards are down to 50 cards only. Therefore,

            p ( C ) = [ Number of black cards ] / [ Total cards in a deck ]

            p ( C ) = [ 26 ] / [ 50 ]

            p ( C ) = 13 / 25

- The entire drawing process consists of 3 events which are dependent on each draw. However, for the overall event to occur i.e drawing a red card , then a face card, and then a black card. We will multiply all three outcomes as follows:

          p ( T ) = p ( A ) * p ( B ) * p ( C )

          p ( T ) = [ 1 / 2 ] * [ 4 / 17 ] * [ 13 / 25 ]

          p ( T ) =  [ 26 / 425 ] ≈ 0.0612

Final answer:

The overall probability of first drawing a red card, then a face card, and then a black card from a standard deck of cards is 0.0124.

Explanation:

This question is related to the concept of probability in Mathematics. A standard deck of cards consists of 52 cards - 26 red (diamonds and hearts) and 26 black (clubs and spades). There are 12 face cards (King, Queen, and Jack of each suit).

For the first draw, the probability of picking a red card is 26/52, which simplifies to 1/2.

After picking a red card, we are left with 51 cards. So, for the second draw, the probability of picking a face card is 12/51.

Then, having picked a red and face card, we are left with 50 cards. For the third draw, the probability of picking a black card is 26/50 which simplifies to 13/25.

We multiply these probabilities together to get the overall probability, therefore (1/2) * (12/51) * (13/25) = 0.012418. Rounding this to four decimal places, we get 0.0124.

Learn more about Probability here:

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You own a share of a stock worth $400 . It decreases 5% .how much is it worth now?

Answers

Answer:

380$

Step-by-step explanation:

Multiply 400*5%=20

Then subtract 400-20=380

Answer:

$380

Step-by-step explanation: