Answer:
15.5
Step-by-step explanation:
In a normal distribution with a mean of 50 and standard deviation of 4, 5% of the values would be less than 43.42.
In a normal distribution, 5% of the values being less than a certain value corresponds to a z-score of -1.645. The formula for a z-score is Z = (X - μ)/σ, where Z is the z-score, X is the value in the dataset, μ is the mean, and σ is the standard deviation.
To solve for X, we use the formula X = Z*σ + μ. Substituting the values for Z (-1.645), σ (4), and μ (50), it gives:
X = (-1.645)*4 + 50 = 43.42
So, in a normal distribution with a mean of 50 and a standard deviation of 4, approximately 5% of the values would be less than 43.42.
#SPJ11
Answer:
20 and 10
Step-by-step explanation:
Answer:
Step-by-step explanation: