b. 5.61 L
c. 11.21 L
d. 22.41 L
e. 44.81 L
Answer:
atoms of isotopes of an element have different numbers of neutrons.
Explanation:
isotopes have the same number of protons, but different numbers of neutrons.
H2SO4
HNO3
NaOH
Any substance that tastes unpleasant in water solution, turns blue litmus paper red, reacts with some metals to release hydrogen, combines with bases to create salts, and stimulates chemical processes is considered an acid. Here among the given options, NaOH is a base. The correct option is D.
Any hydrogen-containing material that has the ability to donate a proton (hydrogen ion) to another chemical is considered an acid. A base is a molecule or ion that can take up an acid's hydrogen ion. Typically, sour tastes help to identify acidic chemicals.
An acid is not NaOH. It is categorized as a base, more specifically a strong base, because it can receive protons from any proton donor and completely dissociates into sodium and hydroxide ions in an aqueous form.
Thus the correct option is D.
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Answer: Identical to its parent.
Explanation:
The cloning can be defined as the process by which genetically identical individuals of an organism is produced either artificially or naturally.
The cloning in case of biotechnology refers to the creating the clones of organisms or copies of cells or DNA of the parent cell that is being used in the process.
The parent cell is cloned and numerous copies is made just like that of the asexual reproduction in the nature.
Example: Dolly the sheep.
A cell created by cloning is genetically identical to its parent. The correct answer is option A.
DNA (deoxyribonucleic acid) is a molecule that carries genetic information and instructions for the development and function of all living organisms.
When a cell is cloned, it is essentially a copy of the original cell. This means that the genetic material in the cloned cell is identical to the genetic material in the original cell.
In conclusion, the correct answer is A) identical to its parent. A cell created by cloning is genetically identical to its parent.
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precipitation
perception
Answer:
Precipitation
Explanation:
Answer:
when 1.00 g of magnesium reacts with 5.00 g of bromine, approximately 7.57 g of magnesium bromide is formed.
Explanation:
To find the mass of magnesium bromide formed when 1.00 g of magnesium reacts with 5.00 g of bromine, you need to first write a balanced chemical equation for the reaction between magnesium and bromine. The balanced equation for the formation of magnesium bromide (MgBr2) is as follows:
Mg + Br2 → MgBr2
Now, you can calculate the molar mass of each substance involved in the reaction:
Molar mass of Mg (magnesium) = 24.31 g/mol
Molar mass of Br2 (bromine) = 2 * 79.90 g/mol = 159.80 g/mol
Molar mass of MgBr2 (magnesium bromide) = 24.31 g/mol + 2 * 79.90 g/mol = 184.11 g/mol
Next, calculate the number of moles for each reactant:
Moles of Mg = Mass (1.00 g) / Molar mass (24.31 g/mol) = 0.0411 moles
Moles of Br2 = Mass (5.00 g) / Molar mass (159.80 g/mol) = 0.0313 moles (approximately, rounded to four decimal places)
Now, determine the limiting reactant. To do this, compare the mole ratio between Mg and Br2 in the balanced equation. The balanced equation shows that 1 mole of Mg reacts with 1 mole of Br2. Therefore, the limiting reactant is the one that is present in the smaller amount relative to the balanced equation's stoichiometry.
In this case, magnesium (0.0411 moles) is present in a smaller amount than bromine (0.0313 moles). So, magnesium is the limiting reactant.
Now that you know magnesium is the limiting reactant, you can calculate the mass of magnesium bromide formed using the stoichiometry of the balanced equation. According to the balanced equation, 1 mole of Mg produces 1 mole of MgBr2.
Moles of MgBr2 formed = Moles of Mg (limiting reactant) = 0.0411 moles
Now, calculate the mass of magnesium bromide formed:
Mass of MgBr2 = Moles of MgBr2 × Molar mass of MgBr2
Mass of MgBr2 = 0.0411 moles × 184.11 g/mol = 7.57 g
So, when 1.00 g of magnesium reacts with 5.00 g of bromine, approximately 7.57 g of magnesium bromide is formed.
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