Part 1: If 1 mol = 6.022 x 10^23 atoms of anything, including Na, then,
4.0 mol Na = 4 x 6.022 x 10^23 atoms Na = 2.4 x 10^24 atoms Na
Part 2: 3.01E23 / 6.022E23 and the answer comes out to .49983394 you would then round this to .500 with significant figures. Hope I helped. :)
1=2.4*10^24 atoms NA
2= .49983394 round this to .500
Hope this helps!
hammer,anvil,eardrum,cochlea
B) what mass of iron(lll) oxide, Fe2O3, must be consumed to prepare 2.50g of iron metal
a. F- concentration decreases
b.the dissociation constant, K, increases
c. HF concentration decreases
d. H+ concentration decreases
When gaseous hydrogen chloride is passed through a sodium chloride solution, precipitation of the sodium chloride occurs as a result of an excess of chloride ions in the solution (caused by the dissociation of HCl). Here the concentration of H⁺ decreases. The correct option is D.
When another electrolyte (which includes an ion that is also present in the first electrolyte, i.e., a common ion) is added, the common ion effect suppresses the ionisation of the first electrolyte. It is thought to be a result of Le Chatlier's principle, often known as the equilibrium law.
An increase in the concentration of one of the ions dissociated in the solution by the addition of another species containing the same ion will result in an increase in the degree of association of ions in a solution where there are several species associating with each other via a chemical equilibrium process.
Here the common ion 'F' in KF supresses the dissociation of HF.
Thus the correct option is D.
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