The correct statements are -
Oxidation state, also known as oxidation number, is a measure of the degree of oxidation or reduction of an atom within a compound or ion. It indicates the number of electrons that an atom has gained or lost, or the hypothetical charge that it would have if all the shared electrons in a compound were assigned to the more electronegative atom.
The oxidation state of an atom can be positive, negative, or zero. In a neutral molecule, the sum of the oxidation states of all the atoms must be zero. In ions or compounds, the sum of the oxidation states of all the atoms must be equal to the overall charge of the species.
Oxidation states are assigned based on a set of rules that consider the electronegativity of atoms, the number of valence electrons, and the distribution of electrons in a molecule or ion. The oxidation state provides information about the reactivity, bonding, and redox reactions of substances. It is often represented by Roman numerals or as a signed integer.
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(x1,y1) (x2,y2)
(32,15) (212,135)
y = mx + b
m=(y2-y1)/(x2-x1)
m=.66667
y = .66667*(x) + b
Plug in #s to test for b value
15 = .66667*(32) + b
b = -6.334
y = mx + b
y = .6667*(x) + (-6.334)
F = .6667*(F) + (-6.334)
F = (.6667*(F) = -6.334
(F - .6667F) = -6.334
F(1 - .6667) = -6.334
F = -19
ThermX = F @ -19 degrees
Brainliest please!
b. 35 g
c. 65 g
d. 6.02 × 1023 g
The gold foil experiment, conducted by Ernest Rutherford, discovered the existence of a small, dense nucleus within an atom, making answer (2) the correct one.
The gold foil experiment was conducted by Ernest Rutherford and led to the discovery of a small, dense nucleus within the atom. This means that the correct answer to your question is (2) contains a small, dense nucleus. Prior to this experiment, the widely accepted model was the 'plum pudding' model, which had negatively charged electrons embedded within a positively charged sphere. The gold foil experiment upended this model as it was discovered that most alpha particles passed through the gold foil undeterred, but a small fraction was deflected at large angles, suggesting that a tiny but dense packet of positive charge — identified as the nucleus — existed in the center of the atom. This discovery led to the formation of the Rutherford atomic model.
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Answer:
The Table helps discover new elements.
Explanation: