To calculate approximately the amount or value of something is called _________.

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Answer 1
Answer: to calculate approximately the amount or value of something is called estimate

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Which situation is best represented by the following equation? 45w + 123.95 = 753.95 A. Erica paid $753.95 for dance classes. She paid a $123.95 registration fee and $45 for each week she was enrolled in the classes. What is w, the number of weeks Erica was enrolled in dance classes? B. Erica paid $753.95 for dance classes. She paid a $45 registration fee and $123.95 for each week she was enrolled in the classes. What is w, the number of weeks Erica was enrolled in dance classes? C. Erica and her sister paid $753.95 for dance classes. Erica paid $123.95 for each week she was enrolled in the classes, and her sister paid $45 for each week she was enrolled in the classes. What is w, the number of weeks Erica and her sister were enrolled in dance classes? D. Erica paid $753.95 for dance classes. She paid $123.95 for each week she was enrolled in the classes after using a coupon that gave her $45 off the price per week. What is w, the number of weeks Erica was enrolled in dance classes?
Scarlett is playing a video game. She spends 900 minerals to create 18 workers. Each worker costs the same number of minerals.

Judith has a necklace with a mass of 65.736 grams. What is the mass of her necklace rounded to the nearest tenth?

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Answer:

65.7 grams.

Step-by-step explanation:

WILL MARK BRAINLIEST PLEASE HELP

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Answer:

  1) h = -1/2t^2 +10t

  2) h = -1/2(t -10)^2 +72

  3) domain: [0, 20]; range: [0, 50]

Step-by-step explanation:

1.) I find it easiest to start with the vertex form when the vertex is given. The equation of the presumed parabolic path for Firework 1 is ...

  h = a(t -10)^2 +50

To find the value of "a", we must use another point on the graph. (0, 0) works nicely:

  0 = a(0 -10)^2 +50

  -100a = 50 . . . . . . subtract 100a

  a = -1/2 . . . . . . . . . divide by -100

Then the standard-form equation is ...

  h = (-1/2)(t^2 -20t +100) +50

  h = -1/2t^2 +10t

__

2.) The path of Firework 2 is translated upward by 22 units from that of Firework 1.

  h = -1/2(t -10)^2 +72

__

3.) The horizontal extent of the graph for Firework 1 is ...

  domain: 0 ≤ t ≤ 20

The vertical extent of the graph for Firework 1 is ...

  range: 0 ≤ h ≤ 50

1
abc14
determine whether each expression is a monomial

Answers

Answer:

15

Step-by-step explanation:

abcdefghijknobeughriuwekhjtwu4igrjsnbei

Let Z={a,c,{a,b}}. What is |Z|?What is the power set of Z?

Which of the following are true?

1. {a,c} ⊆ Z

2. a ∈ Z

3. {c} ⊆ Z

4. {c} ∈ Z

5. b ∈ Z

6. {a,b} ∈ Z

Answers

Z=\{a,c,\{a,b\}\}

\boxed{|Z|=3} (treat \{a,b\} as one element of Z)

The power set of Z is

\boxed{2^Z=\bigg\{\{\},\{a\},\{c\},\big\{\{a,b\}\big\},\{a,c\},\big\{a,\{a,b\}\big\},\big\{c,\{a,b\}\big\},\big\{a,c,\{a,b\}\big\}\bigg\}}

1. \{a,c\}\subseteq Z is true because both a\in Z and c\in Z.

2. a\in Z is true.

3. \{c\}\subseteq Z is true (same reason as part 1).

4. \{c\}\in Z is false because Z does not contain the set \{c\}, rather just the element c itself.

5. b\in Z is false because the element b on its own simply is not in Z. That b\in\{a,b\} does not mean b\in Z, but that b belongs to a subset of Z.

6. \{a,b\}\in Z is true.

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 circuits is tested, revealing 12 defectives.(a) Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool. Round the answers to 4 decimal places.< p\l>(b) Calculate a 95% upper confidence bound on the fraction of defective circuits. Round the answer to 4 decimal places

Answers

Answer:

(a) 0.0178 <= p <= 0.0622

(b) p <= 0.0586

Step-by-step explanation:

We have that the sample proportion is:

p = 12/300 = 0.04

(to)

For 95% confidence interval alpha = 0.05, so critical value of z will be 1.96

Therefore, we have that the interval would be:

p + - z * (p * (1-p) / n) ^ (1/2)

replacing we have:

0.04 + - 1.96 * (0.04 * (1-0.04) / 300) ^ (1/2)

0.04 + - 0.022

Therefore the interval would be:

0.04 - 0.022 <= p <= 0.04 + 0.022

0.0178 <= p <= 0.0622

(b)

For upper bounf z-critical value for 95% confidence interval is 1.645, so upper bound is:

p + z * (p * (1-p) / n) ^ (1/2)

replacing:

0.04 + 1.645 * (0.04 * (1-0.04) / 300) ^ (1/2)

0.04 + 0.0186 = 0.0586

p <= 0.0586

A null hypothesis is that the mean nose lengths of men and women are the same. The alternative hypothesis is that men have a longer mean nose length than women. A statistical test is done and the p-value is 0.225. Which of the following is the most appropriate way to state the conclusion? a. The mean nose lengths of the populations of men and women are identical. b. There is not enough evidence to say that the populations of men and women have different mean nose lengths. c. Men have a greater mean nose length. d. The probability is 0.225 that men and women have the same mean nose length

Answers

Answer:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.

See explanation below.

Step-by-step explanation:

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different (men have longer mean nose length than women), the system of hypothesis would be:

Null hypothesis:\mu_(men) \leq \mu_(women)

Alternative hypothesis:\mu_(men) > \mu_(women)

Assuming that we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_(men)-\bar X_(women)}{\sqrt{(\sigma^2_(men))/(n_(men))+(\sigma^2_(women))/(n_(women))}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Let's assume that the calculated statistic is z_(calc)

Since is a right tailed test test the p value would be:

p_v =P(Z>z_(calc))=0.225

And we know that the p value is 0.225. If we select a significance level for example 0.05 or 0.1 we see that p_v >\alpha

And on this case we have enough evidence to FAIl to reject the null hypothesis that the means are equal. So then the best conclusion would be:

b. There is not enough evidence to say that the populations of men and women have different mean nose lengths.