Answer:
n=3.8416≅4
So Minimum Sample Size is 4
Step-by-step explanation:
In order to find the minimum sample size, the formula we use will be:
Where:
n is sample size
Z is the distribution
S is the standard deviation
E is the Margin of error
S=3 ,E=3
For Z:
Alpha=1-0.95=0.05
Alpha/2=0.025=2.5%
From Cumulative Standard Distribution Table:
Z at Alpha/2 = 1.960
n=3.8416≅4
So Minimum Sample Size is 4
The recursive formula for the given sequence as required in the task content is; f(n) = f (n - 1) - 50.
It follows from the task content that the recursive formula for the given sequence is to be determined.
By observation, the sequence is an arithmetic progression and the common difference, d can be evaluated as;
d = 750 - 800 = 800 - 850 = 850 - 900 = -50
Also, since the recursive formula for an arithmetic sequence takes the form;
f(n) = f (n - 1) + d.
Hence, since the recursive formula as required is;
f(n) = f (n - 1) - 50.
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Answer:
f(1)=900
f(n)=f(n-1)-50if n>1
Step-by-step explanation:
this is the correct
(Do not simplify.)
The expression that represents the elevation is 5,776-(-9)=5,785.
Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
Given that at its highest point, the elevation of a county is 5,776 feet above sea level. At its lowest point, the elevation of the county is 6 feet below sea level.
The expression will be generated by subtracting the two heights.
5,776-(-9) = 5,785.
Therefore, the expression that represents the elevation is 5,776-(-9)=5,785.
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Answer:
5,776-(-9)
positive
5,785
Step-by-step explanation:
Write an integer that represents the elevation of a county feet below sea level.
Which floor do you live on?
Simplify
Answer:
the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)
Step-by-step explanation:
Since the random variable X= length of component chosen at random , is normally distributed, we can define the following standardized normal variable Z:
Z= (X- μ)/σ
where μ= mean of X , σ= standard deviation of X
for a length between 4.98 cm and 5.02 cm , then
Z₁= (X₁- μ)/σ = (4.98 cm - 5 cm)/0.02 cm = -1
Z₂= (X₂- μ)/σ = (5.02 cm - 5 cm)/0.02 cm = 1
therefore the probability that the length is between 4.98 cm and 5.02 cm is
P( 4.98 cm ≤X≤5.02 cm)=P( -1 ≤Z≤ 1) = P(Z≤1) - P(Z≤-1)
from standard normal distribution tables we find that
P( 4.98 cm ≤X≤5.02 cm) = P(Z≤1) - P(Z≤-1) = 0.841 - 0.159 = 0.682 (68.2%)
therefore the probability that he length of this component is between 4.98 and 5.02 cm is 0.682 (68.2%)