Answer:
go to calculator
Step-by-step explanation:
calculator
Answer:
x= -3
Step-by-step explanation:
Answer:
No correlation
Step-by-step explanation:
Hey there! :)
This has no correlation because all the points are spread out throughout the graph making no correlation.
Answer:
D no correlation
Step-by-step explanation:
too many scattered dot all over the place if its some going up down its NO CORRELATION!!!
Answer:
52 weeks
Step-by-step explanation:
The club starting with $270 (club 1) is increasing their bank balance each week by ...
... $280 -270 = $10
The club starting with $10 (club 2) is increasing their bank balance each week by ...
... $25 -10 = $15
Club 2 is gaining on Club 1 by $15 -10 = $5 each week. So, the initial difference of $270 -10 = $260 will be overcome in ...
... $260/($5/week) = 52 weeks
_____
The same result is shown in the attached graph, which also shows that both clubs' bank balances will be $790 at that time.
Answer:
The student can proceed with the calculation of the confidence interval for the difference in population proportions. This is because, from the data she has, 3/4 of the Business students admitted to cheating while 1/2 of the Nursing students admitted to cheating also.
This is above the average number of students in her given sample size which is valid for extrapolation to the College Majors being investigated.
Step-by-step explanation:
Answer:
- The values of x and y that minimize the function, subject to the given constraint are 6 and 8 respectively.
- The minimum value of the function = -44
Step-by-step explanation:
The Lagrange multiploer method finds the optimum value of a multivariable function subjected to a given constraint
It replaces the function with a Lagrange equivalent which is
L(x, y) = F(x, y) - λ C(x, y)
where λ Is the lagrange multiplier which can be a function of x and y
F(x, y) = x² - 10x + y² - 14y + 28
C(x, y) = x + y - 14
L(x, y) = x² - 10x + y² - 14y + 28 - λ (x + y - 14)
We now take the partial derivatives of the Lagrange function with respect to x, y and λ respecrively. Then solving to obtain values of x, y and λ that correspond to the minimum of the function. Since the first partial derivatives are all equal to 0 at minimum point.
(∂L/∂x) = 2x - 10 - λ = 0 (eqn 1)
(∂L/∂y) = 2y - 14 - λ = 0 (eqn 2)
(∂L/∂λ) = x + y - 14 = 0 (eqn 3)
Equating eqn 1 and 2
2x - 10 - λ = 2y - 14 - λ
2x - 10 = 2y - 14
2y = 2x - 10 + 14
2y = 2x + 4
y = x + 2 (eqn *)
Substitute eqn ^ into eqn 3
x + y - 14 = 0
x + x + 2 - 14 = 0
2x - 12 = 0
2x = 12
x = 6
y = x + 2 = 6 + 2 = 8
2x - 10 - λ = 0
12 - 10 - λ = 0
λ = 2
The values of x and y that minimize the function are 6 and 8 respectively.
F(x, y) = x² - 10x + y² - 14y + 28
At minimum point, x = 6, y = 8
F(x, y) = 6² - 10(6) + 8² - 14(8) + 28 = 36 - 60 + 64 - 112 + 28 = -44
Hope this Helps!!!