Answer:
2:3
Step-by-step explanation:
Ratio is indicated by :
Its dogs to cats, right so ratio is number of dogs:number of cats which is 2:3
Hope this helps plz mark brainliest if correct :D
Answer:
2:3
Step-by-step explanation:
2 is first and 3 is the second number so you put them in order
The height of the water when poured into the empty wide cylinder is;
Option A; To the 7¹/₃ mark
Formula for volume of a cylinder is;
V = πr²h
where;
r is radius
h is height
We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;
V_wide = 4πR²
Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;
V_narrow = 6πr²
Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;
V_wide = V_narrow
4πR² = 6πr²
⇒ R²/r² = 6/4
simplifies to get; R²/r² = ³/₂
Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;
πR²H = 11πr²
R²/r² = 11/H
Earlier, we saw that R²/r² = ³/₂. Thus;
11/H = ³/₂
H = 22/3
H = 7¹/₃
The complete question is;
Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
A) To the 7¹/₃ mark
B)To the 8th mark
C) To the 7¹/₂mark
D)To the 9th mark
E) To the 11th mark
Read more at; brainly.com/question/16760517
Answer:
COMPLETE QUESTION:
To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?
a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark
e)To the 11th mark
ANSWER : Option D (To the 7 1/3 mark)
Step-by-step explanation:
First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e
Volume of cylinders
π x R² x 4 = πxr²x 6
R²/r² = 6/4
after both cylinder were emptied
π x R² x h = π x r² x 11
R²/r² = 6/4 = 11/h
h = (4 x 11) /6 = 22/3 = 7 1/3 mark
Therefore, the height of the water in the wide cylinder is 7 1/3
Answer:
B) 74 degrees
Step-by-step explanation:
three angles = 180
2x+32=180
2x=148
x=74
Hope this helps plz hit the crown :D
Answer:
i think B which is 74
Step-by-step explanation:
Answer:
k/9 < 1/3
k < 3
Step-by-step explanation:
quotient is division
k/9 < 1/3
Multiply each side by 9
k < 9/3
k < 3
80
120
48
144
Answer:
144
Step-by-step explanation:
first digit of the code: only 2 and 4 are the only even numbers availible, so only 2 possibilities for the first digit.
2nd digit of code: 2,5,7,9,1 so 6 possibilities for the 2nd digit.
3rd digit of code: 2,5,7,9,1 so 6 possibilities for the 3rd digit.
4th digit of code: only 7 and 9 are greater tyhan 6 so only 2 possibilities for the 4th digit.
SO...
2 x 6 x 6 x 2 = 144
Answer:
Step-by-step explanation:
Answer:
52
Step-by-step explanation:
78 divided by 3 is 26
26 times 2 is 52