Someone solve asap whats the answer for this

Answers

Answer 1

Answer:

Answer: The answer is in the 1st image.

Explanation: The explanation is in the 2nd image.

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a random sample of 130 students is chosen from a population of 4,500 students. if the mean iq in the sample is 120 with a standard deviation of 5, what is the 99% confidence interval for the students' mean iq score? answers given below: 118.87−121.13 107.12−132.88 125−135 115−125

Answers

Answer with explanation:

Total Sample Size = 4,500 Students

Sample Chosen(n) = 130 students

Mean IQ of the Sample, $\bar{X} = 120$

Standard Deviation, $\sigma=5$

To Calculate 99% confidence interval for the students' mean IQ score, we will calculate,

$Z_(99 percent)=2.58$

Formula for Confidence Interval

$=\bar{X} \pm Z_(99 percent)* (\sigma)/(√(n))\n\n=120 \pm 2.58 * (5)/(√(130))\n\n=120 \pm (12.9)/(11.401)\n\n =120 \pm 1.1314\n\n=120 \pm 1.13$

The Value of Confidence interval will lie between

⇒ 120 - 1.13 to 120 +1.13

⇒118.87 to 121.13

Option A: 118.87−121.13

$C.I.=120 \pm z_( \alpha /2) ( \sigma )/( √(n) ) \n =120 \pm 2.58 * (5)/( √(130) ) \n =120 \pm 1.13 \n =118.87 - 121.13$

Suppose you choose a marble from a bag containing 3 red marbles, 3 white marbles, and 5 blue marbles. You return the first marble to the bag and then choose again. Find P(red and blue).

Answers

The answer is 15/121.

Since we have red AND blue, that means that both of these events occur, so we will use the multiplication rule and multiply these two probabilities:

- A probability of choosing a red marble: 3/11. (because there are 3 marbles out of total 11 marbles)
- A probability of choosing a blue marble after the red one: 5/11. (because there are 3 marbles out of total 11 marbles; there are 11 in total again because the first marble has been returned)

So, P(red and blue) is 3/11 * 5/11 = (3*5)/(11*11) = 15/121

Sarah described the following situation:When fertilizer was added to one plant and nothing was added to another plant, there was a noticeable difference in the color of the leaves of the plants.

Which of the following best describes the situation?

A. This is an example of correlation but not causation.

B. This is an example of causation but not correlation.

C. This is an example of both correlation and causation.

D. This is an example of neither correlation nor causation.

Answers

When Sarah added the fertilizer and there was a noticeable difference, we can say that:

B. This is an example of causation but not correlation.

What is Causation?

Causation occurs when an effect is noticed because of a traceable item. The traceable item, in this case, is the fertilizer.

So when the fertilizer was added and a change in color was noticed, we can deduce that the difference was because of the fertilizer.

Therefore, option B is correct.

Learn more about causation here:

brainly.com/question/12479370

#SPJ5

Answer: B.) This is an example of causation but not correlation.

Step-by-step explanation: Causation is a cause and effect, because fertilizer was added to one plant, it's leaf color was improved.

A man buys 12.50kg of one of rice for £30 per kg and £67.90 per kg. If he mixes them and makes packets, each containing 3450g of rice, how many packets of rice are there and what is the cost of each packet?

Answers

Answer:

a. The number of packets the two bags/brands of rice can be repackaged to = 7 packets.

b. Cost of one packet is £174.82

Step-by-step explanation:

Please kindly see the attached files for explanation.

What is the y-intercept of the line?

y= -2x - 8

y-intercept =

Answers

Like I said on the other question. Slope will ALWAYS be the number beside x and y-intercept will always be after that.

Slope-intercept form = y = mx + b

Slope goes where m is and y-intercept goes where b is.

Hope this helps!

Answer:

-8

Step-by-step explanation:

Solve 8m² + 20m = 12 for m by factoring

Please show all work

Answers

$8m^(2)+20m=12 / :2$
$4m^(2)+10m=6$
$4m^(2)+10m-6 =0$
$\Delta=b^(2)-4ac$
$\Delta=100-(4*4*-6)$
$\Delta=100+96=196$
$x1=(-b-√(\Delta))/(8)$
$x1=(-10-14)/(8)$
$x1=(-24)/(8)$
$x1=-3$
$x1=(-b+√(\Delta))/(8)$
$x2=(-10+14)/(8)$
$x2=(1)/(2)$

so you can write $8m^(2)+20m=12 / :2$ as

$8(m+3)(m-(1)/(2))=8*[m^(2)+2.5m-1.5]=0$

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