The rectangular coordinate of the given polarcoordinate will be (- 3.5,6.062).
A pair of numbers that employ the horizontal and vertical distinctions from the two reference axes to represent a point's placement on a coordinate plane. typically expressed by the x-value and y-value pairs (x,y).
Coordinates are always written in the form of small brackets the first term will be x and the second term will be y.
As per the given polar coordinates,
(7, 2π/3)
It is known that, x = r cosθ and y = r sinθ.
x = 7 cos(2π/3) and y = 7 sin(2π/3)
x = -3.5 and y = 6.062
Hence "The rectangular coordinate of the given polarcoordinate will be (- 3.5,6.062)".
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Answer: The annual interest rate is 1.06%
Step-by-step explanation: This is a simple interest computation.
The formular for a simple interest is given as;
I = (P ×R × T)/100
Where I represents the interest paid,
P represents Principal borrowed at the beginning
R represents the rate at which the interest is calculated
T represents the Time measured in number of years
If the interest is calculated as I = (P×R×T)/100, we should first of all make R the subject of the formular;
Multiply both sides by 100
100I = P×R×T
Divide both sides of the equation by P and T
(100I)/(P × T) = R
Now we can insert the values into the rearranged formular
(100 × 143)/(4500 × 3) = R
14,300/13,500 = R
143/135 = R
1.0592592593 = R
Therefore, R which is the rate of interest equals approximately 1.06%
Answer:
360
Step-by-step explanation:
deltamath
B. 9 inches
C. 20.25 inches
D. 10 inches
Answer:
Step-by-step explanation:
The area of a square is found in the formula
We have the Area value so we will plug it in:
Take the square root of both sides to undo the square on the s to get that
s = 9
Answer: See explanation
Step-by-step explanation:
Your question isn't really clear. Let me help you rephrase it and solve.
Let's say Cesar is creating a schedule to practice his instrument for band. He needs to practice for a total of 10 hours in a week. On Monday he practice for 1 1/2 hours, on Tuesday he practiced for 2 1/4 hours, and on Wednesday he practiced for 1 1/2 hours.
The total hours that Cesar has used in practicing will be:
= 1 1/2 + 2 1/4 + 1 1/2
= 5 1/4
To get the number of hours that Cesar need to practice during the rest of the week in order to have his 10 total hours, we subtract 5 1/4 hours from 10 hours. This will be:
= 10 - 5 1/4
= 4 3/4 hours.
Cesar needs to practice for 4 3/4 hours more.