MATHEMATICS HIGH SCHOOL

an article was sold for $560 inclusive of a 20% discount. what was the price before the discount was given?

Answers

Answer 1

Answer:

Answer:

672

Step-by-step explanation:

(1. Turn the percent into a decimal) 20% = 0.20 (2. Multiply 560 x 0.20 = 112) (3. Add 560 + 112)

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A telephone pole 13 1/3 feet tall casts a shadow of 16 feet when a person casts a shadow of 6 feet. How tall is the person?

Answers

Five feet tall or 5 feet tall or 60 inches.

Answer:

5 feet tall

Step-by-step explanation:

im on odessy this is right

A recent survey by the cancer society has shown that the probability that someone is a smoker is P(S)=0.19. They have also determined that the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158. What is the probability (rounded to the nearest hundredth) that a random person is a smoker and has lung cancer P(S∩LC) ?0.35

0.03

0.02

0.83

Answers

Answer:

P (S∩LC) = 0.03

Step-by-step explanation:

We are given that the probability that someone is a smoker is P(S)=0.19 and the probability that someone has lung cancer, given that they are a smoker is P(LC|S)=0.158.

Given the above information, we are to find the probability hat a random person is a smoker and has lung cancer P(S∩LC).

P (LC|S) = P (S∩LC) / P (S)

Substituting the given values to get:

0.158 = P(S∩LC) / 0.19

P (S∩LC) = 0.158 × 0.19 = 0.03

Jack wants to fill a rectangular box with sand. The length of the sand box is 3 feet, width is 6 inches, and height is 2.4 inches. Each bag of sand contains 0.15 cubic foot of sand. How many bags of sand will Jack need to fill the box completely?

Answers

To answer the problem above, determine first the volume of the rectangular box by multiplying the dimensions. The length is 3 feet, width is 6 inches which is equal to 0.5 feet, and the height is 2.4 inches which is equal to 0.2 ft. The volume is 0.3 ft^3. To determine the number of bags of sand needed, divide the volume or rectangular box by the volume of sand, 0.15 ft^3. Thus, Jack needs 2 bags of sand.

Answer:

he would need 2 bags of sand

36x6x2.4 = 518.4

.15 cubic feet is 259.2 cubic inches

518.4 divided by 259.2 = 2

Step-by-step explanation:

n a right triangle, the tangent of angle A is 912 and the cosine of angle A is 1215. Based on these values, what is the sine of angle A? A 915 B 1516 C 1115 D 11120

Answers

Answer:

Option A $sin(A)=(9)/(15)$

Step-by-step explanation:

we know that

$tan(A)=sin(A)/cos(A)$

Solve for sin(A)

$sin(A)=tan(A)cos(A)$

we have

$tan(A)=(9)/(12)$

$cos(A)=(12)/(15)$

substitute

$sin(A)=(9)/(12)((12)/(15))$

$sin(A)=(9)/(15)$

Final answer:

The sine of angle A can be found using the relationship between the tangent and cosine of angle A. By substituting the given values into the sine identity, we can determine that the sine of angle A is 915.

Explanation:

To find the sine of angle A, we can use the trigonometric identity: sin A = opposite/hypotenuse. Given that the tangent of angle A is 912 and the cosine of angle A is 1215, we can use the relationship between these trigonometric functions. Since tan A = opposite/adjacent and cos A = adjacent/hypotenuse, we can substitute these values into the identity to solve for the sine of angle A.

From tan A = 912, we can rearrange the equation to get opposite/adjacent = 912.

From cos A = 1215, we can rearrange the equation to get adjacent/hypotenuse = 1215.

Substituting these values into the sine identity, we get sin A = opposite/hypotenuse = (912)(1215).

Therefore, the sine of angle A is 915.

Learn more about Trigonometry here:

brainly.com/question/11016599

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Please help how do I do this ??

Answers

for 10 here is the answer and for 9 i’ll reply to my comment

Xsquared + 3x - 5 solved using the quadratic formula

Answers

$x^2+3x-5=0\na=1;\ b=3;\ c=-5\n\n x=(-b^+_-√(b^2-4ac))/(2a)\n\nx=(-3+√(3^2-4\cdot1\cdot(-5)))/(2\cdot1)\quad\vee\quad x=(-3-√(3^2-4\cdot1\cdot(-5)))/(2)\n\nx=(-3+√(9+20))/(2)\quad\vee\quad x=(-3-√(9+20))/(2)\n\nx=(-3+√(29))/(2)\quad\vee\quad x=(-3-√(29))/(2) \n\nx\approx1.19\quad\vee\quad x\approx-4.19$