A ball rolls down an incline with an acceleration of 10 cm/s^2. If it starts with an initial velocity of 0 cm/s and has a velocy of 50 cm/s when it reaches the bottom of the ramp, how long is the ramp?

Answers

Answer 1

Answer: Given a = 10 cm/s²
u = 0 cm/s
v = 50 cm/s
we know that
v²=u²+2aS
2500=2×10×S
2500÷20 = S
S= 125 cm
The ramp is 125 cm

Answer 2

Answer:

Final answer:

The time for the ball to reach the bottom of the ramp is 5 seconds. Using this time value, the acceleration, and the initial velocity, you can calculate the length of the ramp, which is found to be 125 cm.

Explanation:

The question involves the physics principles of kinematics, specifically the concept of acceleration. Given that the initial velocity is 0 cm/s, the final velocity is 50 cm/s, and the acceleration is 10 cm/s^2, you can find the time it took for the ball to reach the bottom using the formula vf=vi+at (Final velocity = initial velocity + acceleration * time). Substituting the given values, you get the equation 50cm/s = 0cm/s + 10cm/s^2 * time, simplifying which gives time = 5 seconds.

To find the length of the ramp, you can use another kinematic equation, d = vit + 0.5at^2 (Distance = initial velocity * time + 0.5 * acceleration * time^2). Substituting the values we know, (initial velocity = 0, acceleration = 10 cm/s^2, time = 5 s), the equation simplifies to d = 0*5 + 0.5*10*5^2 = 0 + 0.5*10*25 = 125 cm. Therefore, the length of the incline or ramp is 125 cm.

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