Part A: The enmeshed cars were moving at a velocity of approximately 8.66 m/s just after the collision.
Part B: Car A was traveling at a velocity of approximately 8.55 m/s just before the collision.
To find the speed of car A just before the collision in Part B, you can use the principle of conservation of momentum.
The total momentum of the system before the collision should equal the total momentum after the collision. You already know the total momentum after the collision from Part A, and now you want to find the velocity of car A just before the collision.
Let's denote:
- v_A as the initial velocity of car A before the collision.
- v_B as the initial velocity of car B before the collision.
In Part A, you found that the enmeshed cars were moving at a velocity of 8.66 m/s at an angle of 60 degrees south of east. You can split this velocity into its eastward and southward components. The eastward component of this velocity is:
v_east = 8.66 m/s * cos(60 degrees)
Now, you can use the conservation of momentum to set up an equation:
Total initial momentum = Total final momentum
(mass_A * v_A) + (mass_B * v_B) = (mass_A + mass_B) * 8.66 m/s (the final velocity you found in Part A)
Plug in the known values:
(1900 kg * v_A) + (1500 kg * v_B) = (1900 kg + 1500 kg) * 8.66 m/s
Now, you can solve for v_A:
(1900 kg * v_A) + (1500 kg * v_B) = 3400 kg * 8.66 m/s
1900 kg * v_A = 3400 kg * 8.66 m/s - 1500 kg * v_B
v_A = (3400 kg * 8.66 m/s - 1500 kg * v_B) / 1900 kg
Now, plug in the values from Part A to find v_A:
v_A = (3400 kg * 8.66 m/s - 1500 kg * 8.66 m/s) / 1900 kg
v_A = (29244 kg*m/s - 12990 kg*m/s) / 1900 kg
v_A = 16254 kg*m/s / 1900 kg
v_A ≈ 8.55 m/s
So, car A was going at approximately 8.55 m/s just before the collision in Part B.
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50. kilometers during the next 0.50 hour, and
40. kilometers in the final 0.50 hour. What is the
car’s average speed for the entire trip?
(1) 45 km/h (3) 85 km/h
(2) 60. km/h (4) 170 km/h
The average speed of the car for the entire trip can be calculate by using:
where S is the total distance covered by the car, and t is the total time taken.
The total distance travelled by the car is:
while the total time taken is:
so, the average speed of the car is:
so, the correct answer is (3) 85 km/h.
The average speed of the car for entire trip is .
Further Explanation:
Speed is the measure of a quantity of an object the tells how fast the object is moving in the other words we can define the speed that it is the distance covered by an body divided by the time taken to cover that distance. It is a quantity with only magnitude so it is a scalar quantity.
The average speed is defined as the sum of all the distance traveled by the body divided by the sum of time taken to travel that distance.
Given:
The distance travel by the car is for .
The distance travel by the car is for .
The distance travel by the car is for .
.
Concept:
The expression for the average can be written as:
S = …… (1)
The distance travel by the car is for , distance travel by the car is for and distance travel by the car is for .
The sum of the distance is:
The sum of time taken to travel the distance is:
Substitute for total distance and for total time in equation (1).
Therefore, the average speed of the car for entire trip is .
Learn more:
1. Find the net force. https://brainly.in/question/8668644
2. Find the velocity. https://brainly.in/question/4502003
3. Calculate average speed brainly.com/question/11597590
Answer Details:
Grade: Middle school
Subject: Physics
Chapter: Kinematics
Keywords:
Highway, car, driven, 80 km, 1.00 hour, 1.00 hr, 1.00 h, 50 km, 0.50 hour, 0.50 hr, 0.50 h, 50 km, average speed, entire, trip, 85 km/hr.
Globular clusters are nearly spherical groups of about 10,000 to 1 million stars. A typical galaxy may contain up to a few hundred globular clusters; our galaxy, the Milky Way, has somewhere between 125 and 200 globular clusters orbiting the galactic center.
Answer:
water pushes against the squid