Answer:
15.7m/s
Explanation:
To solve this problem, we use the right motion equation.
Here, we have been given the height through which the ball drops;
Height of drop = 14.5m - 1.9m = 12.6m
The right motion equation is;
V² = U² + 2gh
V is the final velocity
U is the initial velocity = 0
g is the acceleration due to gravity = 9.8m/s²
h is the height
Now insert the parameters and solve;
V² = 0² + 2 x 9.8 x 12.6
V² = 246.96
V = √246.96 = 15.7m/s
1.2 s
0.66 s
0.53 s
Regions of compression and rarefaction help define _______.
Electromagnetic waves
Longitudinal waves, but not transverse waves
Transverse waves, but not longitudinal waves
All mechanical waves
B)0.944
C)1.21
D)1.06
The equation for the index of refraction is n = sin(theta1)/sin(theta2) where theta1 is the refracted angle and theta2 is the angle in a medium. Plugging in the values for the index of refraction, n = sin(32)/sin(26) we get 1.21. the answer is letter C. The index of refraction is always greater than 1.
That answer is wrong it is not 1.21 just turned it in and was wrong
If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then the traveler's total displacement would be 51.30 kilometers.
An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.
As given in the problem If a traveler first drives 18.6 km east, then 30.3 km southeast, and finally 10.7 km south then we have to find the traveler's total displacement,
the total displacement in the east direction = 18.6 + 30.3Cos45°
the total displacement in the east direction = 40 km
the total displacement in the south direction = 10.7 + 30.3Cos45°
the total displacement in the south direction = 32.12 km
The net resultant displacement = √(40² + 32.12²)
The net resultant displacement = 51.30 kilometers
Thus, the traveler's total displacement comes out to be 51.30 kilometers.
Learn more about displacement here, refer to the link;
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