Based on the law of conservation of energy, how can we reasonably improve a machine’s ability to do work?Move the machine to a different gravitational field.

Increase the friction between its moving parts.

Reduce the friction between its moving parts.

Redefine the machine’s system boundaries.

Answers

Answer 1

Answer:

Based on the law of conservation of energy, we know that we can't create energy, machines can only convert one type of energy into another. So, if we want to improve a machines ability then we need to reduce it's loss energy (part of energy which is useless).

What is the law of conservation of energy ?

"The law of conservation of energy states that the amount of energy is neither created nor destroyed. For example, when you roll a toy car down a ramp and it hits a wall, the energy is transferred from kinetic energy to potential energy."

What is energy ?

"Energy is defined as the “ability to do work, which is the ability to exert a force causing displacement of an object.” Energy is just the force that causes things to move. Energy is divided into two types: potential and kinetic.

Know more about energy here

brainly.com/question/1932868

#SPJ3

Answer 2

Answer: Based on the law of conservation of energy, we know that we can't create energy, machines can only convert one type of energy into another. So, if we want to improve a machines's ability then we need to reduce it's loss energy (part of energy which is useless). Out of all the options only Option C fits best with it.

In short, Your Answer would be Option C

Hope this helps!

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It takes 167 kJ of work to accelerate a car from 20.9 m/s to 27.9 m/s. What is the car's mass?

Answers

Answer:

space without opposite should be served

What is a light year??????????

Answers

A light-year is a distance.

It's the distance that light travels through vacuum in one year.

The distance is 9.4607 x 10¹² kilometers in metric units, and 5.8786 x 10¹² miles
in 'customary' units, and is normally written without a bunch of question marks.

A light year is an unit of distance.

$light year$ ≈ $10^1^3km$

Where is the field of each charge the strongest ?(A. positive charge arrows pointed out)
(B.negative charge arrows pointed inward)

Answers

First we have to agree on what you mean by "strongest".

To me, "strongest" means the place where it exerts the greatest
force on another charge that happens to be passing by.

In both cases ... 'A' and 'B' ... that's going to be right smack on top
of the charge itself, or as close to it as you can get.

On drawings, it's the spot where the field 'lines' are closest together.

It makes no difference whether the original charges are positive or negative.

An internal combustion engine uses fuel, of energy content 44.4 MJ/kg, at a rate of 5 kg/h. If the efficiency is 28%, determine the power output and the rate of heat rejection

Answers

Efficiency = Power Output / Power Input

Power Input = Rate of Energy input = 44.4 MJ/kg * 5 kg/h

= 222 MJ/h

But 1 hour = 3600seconds

222 MJ/h = 222 MJ/3600s = 0.061667 MW J/s = Watts

Power input = 0.061667 MW = 61 667 W

From Efficiency = Power Output / Power Input

   28% = Power Output / 61667

   Power Output = 0.28 * 61667

   Power Output = 17266.76 W

Power Output = 17 267 W

Rate of heat Rejection = Power input - Power output

      = 61667 - 17267 = 44400 W

Rate of heat Rejection = 44 400 W.

C- Copyright.

How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?

Answers

Answer: Force = 81.6 N

Explanation:
According to Newton's Second law:
F = ma --- (1)

Where F = Force = ?
m = Mass = 68 kg
a = Acceleration = 1.2 m/s^2

Plug in the values in (1):
(1) => F = 68 * 1.2
F = 81.6 N (The force needed to accelerate the skier at a rate of 1.2 m/s^2)

Answer:

The force needed to accelerate a 68 kilogram-skier at a rate of 1.2ms2 is 81.6 Net forces

Explanation:

Una sustancia radioactiva, cuya temperatura es inconstante, aumenta su temperatura en 30ºF, luego disminuye e 40ºC, luego aumenta en 12R y por último disminuye en 10K; entonces la temperatura final de dicha sustancia: a) No varia b) Aumenta en 24R c) Disminuye en 48R d) Aumenta en 48R e) Disminuye en 24R