A child is sending pulses down a stretched rope at a rate of 2 pulses per second. The distance between the pulses is 5 meters. What is the speed of the wave?a. 5 m/s
c. 2 Hz
b. 10 m/s
d. 2.5 m/s User: Longitudinal seismic waves are known as
a. primary waves.
b. secondary waves.
c. surface waves.
d. transverse waves.

Answers

Answer 1
Answer:
Wave speed  =  (wavelength) x (frequency)

                       =     (5 meters)  x  (2 per second)

                       =        10 meters per second .

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When 10 N force applied at 30 degrees to the end of a 20 cm handle of a wrench, it was just able to loosen the nut. What magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle

Answers

Answer:

5N

Explanation:

To get the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle, we will have to resolve the force perpendicular to the wrench. Torque is the turning effect of a body or force about a point. It is similar to moments.

Torque = Force * radius

Note that the force must be perpendicular to the wrench. On resolving the force perpendicularly to the wrench, we will have to resolve the force to the vertical.

Fy = Fsinθ

Fy = 10sin30°

Fy = 10 * 0.5

Fy = 5N

Torque = Fy * r

Given Fy = 5N and r = 20cm = 0.2m

Torque = 5 * 0.2

Torque = 1Nm

Hence the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle is 5N

Jason hits a volleyball with an initial velocity of 6 meters per second straight up. if the back starts at 2 meters above the floor how long will the ball be in the air

Answers

Vi = 6 m/s 
d = -2 m 
a = - 9.81 m/s^2 
t = ? 
Formula 
d = vi*t + 1/2 a t^2 
- 2 = 6m/s *t - .5 * 9.81 * t^2 
Put the - 2 on the right. 
4.905 t^2 + 6 m/s t +2 = 0 
 a = -4.905 m/s^2 
b = 6 m/s 
c = 2 m 
t = [- b +/- square root(b^2 - 4ac)]/(2a) 
t = [ -6 +/- square root (6^2 - 4*(-4.905)*2)] / (- 4.905*2) 
t = [-6 +/- 8.674) / - 9.81 
t = -14.674/-9.81 
t = 1.69 seconds. 

How much energy ( in joules ) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature ? A. 697.08 J
B. 17,705.1 J
C. 20,075.04 J
D. 51,302.88 J

Please include how you got your answer , thank you.

Answers

Answer:

B. 17,705.1 J

Explanation:

The hear released when the mercury condenses into a liquid is given by:

Q=m \lambda_v

where

m = 0.06 kg is the mass of the mercury

\lambda_v is the latent heat of vaporization

For mercury, the latent heat of vaporization is \lambda_v = 296 kJ/kg, so the heat released during the process is:

Q=(0.06 kg)(296 kJ/kg)=17.76 kJ = 17,760 J

So, the closest option is

B. 17,705.1 J

The energy ( in joules ) released when 0.06 kilograms ofmercury is condensed to a liquid at the same temperature is about 697.08 J. inother to solve this problem, should know the latent heat of fusion of mercurywhich is equal to about 11.4 kJ/kg and multiplying by mass of mercury.

The type of radiation that will penetrate farthest into a material isA. a beta ray.


B. a gamma ray.


C. an X-ray.


D. an alpha ray.


E. They all penetrate material the same distance

Answers

my answer is E.  If am wrong then plz tell me whats the right

The kinetic energy of a book on a shelf is equal to the work done to lift the book to the shelf. t/f

Answers

Answer: The given statement is false.

Explanation:

Kinetic energy is defined as the energy obtained by an object because of its motion.

For example, moving a pulley on the road.

Whereas energy of an object obtained due to its position is known as potential energy.

For example, lifting a book from table to the shelf shows position of the book has changed.

Therefore, we can conclude that the statement kinetic energy of a book on a shelf is equal to the work done to lift the book to the shelf, is false.

The kinetic energy of a book on a shelf is equal to the work done to lift the book to the shelf is false. The kinetic energy on the shelf is zero because it is not in action.

A printer has a power of 100 W. It takes 30 seconds to print out a document. How much energy will ithave used?

Answers

A printer has power of 100 W, and it takes time of 30 seconds to print out the document, then the power consumed in 30 seconds will be 0.8333 W.

What is Power?

The quantity of energy moved or changed per unit of time is termed as power in physics. The watt, or one joule per second, is the unit of power in the International System of Units. Power is also referred to as activity in historical texts. A scalar quantity is power.

Power is connected to other factors; for instance, the power required to move a land vehicle is equivalent to the sum of the vehicle's velocity, traction force on its wheels, and aerodynamic drag.

Assuming the printer consumes electrical energy at a steady rate, then:

100 ÷ 60 = 1.6667 watts per minute.

Now, calculate the power consumed in 30 seconds,

1.6667 ÷ 2 = 0.8333 watts.

Therefore, the power consumed in 30 seconds will be 0.8333 watts.

To know more about Power:

brainly.com/question/27442707

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100W translates to 100 watts consumed in 1 hour. Assuming the printer consumes electrical energy at a steady rate, then: 100 ÷ 60 = 1.6667 watts per minute. 1.6667 ÷ 2 = 0.8333 watts consumed in 30 seconds.