What’s the kinetic energy of the object? Use .Erica is competing in the shot put event at a track meet. She hurls a shot with a mass of 4 kilograms at a speed of 9 meters/second. The shot’s kinetic energy is joules.

Answers

Answer 1

Answer:

The kinetic energy of an object varies directly with the square of the speed of an object. The required kinetic energy of the shot is f 162 J.

What is Kinetic Energy?

The energy possessed by an object by its motion is known as the object's kinetic energy. It depends on the speed and mass of the given object.

Given data -

The mass of shot put is, m = 4 kg.

The speed of shot put is, v = 9 m/s.

The mathematical expression for the kinetic energy of the shot put is,

$KE = (1)/(2) m v^(2)$

Solving as.

$KE = (1)/(2) * 4 * 9^(2)\n\nKE = 162 \;\rm J$

Thus, we can conclude that the required kinetic energy of the shot is of 162 J.

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Answer 2

Answer:

Answer:

We have: K.E. = mv² / 2

here, m = 4 Kg

v = 9 m/s

Substitute their values into the expression:

K.E. = (4)(9)² / 2

K.E. = (4)(81) / 2

K.E. = 324 / 2

K.E. = 162 Joules

Explanation:

In short answer: it would be K.E.=162 Joules

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A rocket travels vertically at a speed of 1300 km/hr.1300 km/hr. The rocket is tracked through a telescope by an observer located 13 km13 km from the launching pad. Find the rate at which the angle between the telescope and the ground is increasing 3 min3 min after the lift-off.

Answers

Final answer:

This calculus problem can be solved by defining the appropriate variables, constructing a relationship using trigonometry, taking the derivative of both sides with respect to time, and solving for the rate of change of the angle with respect to time. The initial distances, rocket's speed, and angle are used to determine the rocket's position after 3 minutes and thus the rate at which the angle is changing.

Explanation:

This problem involves the concept of related rates in calculus and the understanding of trigonometric relationships. Let's denote the rocket's altitude as y and the angle between the ground and the telescope as θ. We know Δy/Δt = 1300 km/hr, we're given the initial distance (13 km), and we want to find Δθ/Δt at 3 min after lift-off.

From trigonometry, we know that tan(θ) = y/x, where x is the horizontal distance (which remains constant at 13 km) and y is the vertical distance (which is changing). Differentiating both sides with respect to t gives sec²(θ) * Δθ/Δt = Δy/Δt / x. Assuming that the speed of the rocket remains constant, we find that y = (1300 km/hr * 3min)*(1hr/60min) = 65 km at 3 min after launch. Plugging x = 13 km and y = 65 km into the equation tan(θ) = y/x, we get θ = atan(65/13) = 78.69°. Now we can solve for Δθ/Δt using the differentiated equation: Δθ/Δt = ( Δy/Δt / x ) / sec²(θ) = (1300 km/hr / 13 km) / sec²(78.69°). Solving this gives the rate of change of θ with respect to time.

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A 10,000-watt radio station transmits at 535 kHz.Determine the number of joules transmitted per second.

Answers

Answer:

Energy is 10,000 Joules.

Explanation:

It is given that, a 10,000 watt radio station transmits at 535 kHz. We have to write the number of joules transmitted per second.

We know that number of joules transmitted per second is called the power. Its SI unit is watts. Mathematically, the power of radio station is given by :

$P=(W)/(t)$

Where

W is the work done by radio station

t is the time taken.

According to relation :

$1\ watt==(1\ Joule)/(1\ seconds)$

So, $10,000\ watt==(10,000\ Joule)/(1\ seconds)$

Hence, energy per second is 10,000 Joules.

If you are given a 10,000-watt radio station transmits at 535 kHz, then you just divide one by 535,000 Hz which is equal to 1.87 x 10^-6 seconds. Multiply this value by 10,000W and you get 0.019 Joules.

Which structure's primary function is to warm and moisten the air?a. nasal cavity
b. epiglottis
c. bronchus
d. bronchiole

Answers

Answer: a. nasal cavity

Explanation:

The nasal cavity is a external opening of the respiratory tract. This involves two canal like cavities through which air enters the respiratory tract and moves out of the body. These are the two hollow spaces within the nose each of which consists of mucus and lined up with the hairs.

The primary function of the two nasal cavities is to moisturize, warm and filter the air entering the respiratory tract. These cavities filter out environmental contaminants like dust, pollen, molds and others.

A.Nasal cavity!!!!!!!!!!!!!!!!!!!!!!!

An alarm clock draws 0.5 A of current when connected to a 120 volt circuit. Calculate its resistance.

Answers

We need to calculate the resistance of a clock which draws current I=0.5A and is connected to a circuit of V=120V. We can find the resistance of a circuit from Ohm's law: I=U/R where I is the current, U is the voltage and R is the resistance. So lets manipulate Ohm's law to find the resistance: R=U/I. Now we input our numbers: R=120V/0.5A and we get R=240 Ohm. So the resistance is R=240 Ohm.

Given the amount of voltage and the amount of current drawn by the alarm clock, its resistance is 240 ohms.

What is Ohm’s law?

Ohm’s law states that "the potential difference between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = I × R

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given the data in the question;

Voltage V = 120V

Current I = 0.5A

Resistance R = ?

We substitute our given values into the expression above.

V = I × R

120V = 0.5A × R

R = 120V / 0.5A

R = 240Ω

Therefore, given the amount of voltage and the amount of current drawn by the alarm clock, its resistance is 240 ohms.

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Most of the Earth's volcanoes occurA.
near the center of tectonic plates.
B.
where there are no tectonic plates.
C.
along tectonic plate boundaries.
D.
before tectonic plates can form.