D.Suitcase
Tricep Curls is not a shoulder and back weight training exercise and is denoted as option B.
This is a form of physical activity which keeps the body fit and improves the general well being.
Tricep Curls work your triceps which is a muscle in the upper arm thereby making it the most appropriate choice.
Read more about Exercise here brainly.com/question/1365564
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Answer:
Explanation:
The sensor contains an LDR which has a resistance of 10kohlms in daylight and 100kohlms in the dark.
If the resistor in the circuit is 1 megaohlm, the total resistance in daylight and darkness will be 1.01 megaohms and 1.1 megaohlms.
The percentage difference = (1.1-1.01)/1.1*100% = 8.18%
If the resistor in the circuit is 25 kohlm, the total resistance in daylight and darkness will be 35 kohms and 125 kohlms.
The percentage difference = (125-35)/125*100% = 72%
With the input p.d to the sensing circuit fixed at 12 v, the sensing current will change according to the total resistance. A 72% difference is much more detectable. So the 25 kohm resistor is the better choice.
Answer:
Explanation:
V=IR
I=12/(R of resistor + R of LDR)
R of LDR = 10kohm in light and = 100kohm in dark
R1 = 25kohm
R2 = 1Mohm
solve 4 current
light dark
R1 12/(25+10)=0.343mA 12/(25+100)=0.096mA
R2 12/(1000+10)=0.012mA 12/(1000+100)=0.011mA
so R1 is better as its easier 2 tell its light or dark
B. a prism.
C. a lens.
D. an analyzer.
The final velocity of the car can be found using the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Plugging in the given values, we find that the car will be traveling at 24 m/s at 6 seconds.
To find the final velocity of a car accelerating at a constant rate, we can use the equation:
v = u + at
Where:
v is the final velocity, u is the initial velocity (which is zero in this case), a is the acceleration (4.0 m/s²), and t is the time (6 seconds).
Plugging in the values, we get:
v = 0 + (4.0 m/s²)(6s) = 24 m/s
Therefore, the car will be traveling at 24 m/s at 6 seconds.
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