The pressure of the sample of gas at 273 K is equal to 0.273 atm assuming the volume is constant.
Gay-Lussac's law can be described as that when the volume of the gas remains constant then the pressure (P) of the gas and the absolute temperature (T) in a direct relationship.
Gay Lussca's law can be described as mentioned below:
P/T = k
The pressure of gas is directly proportional to absolute temperature of the gas.
P ∝ T ( Volume of gas is constant)
or, P₁/T₁ = P₂/T₂ .................(1)
Given, the initial temperature of the gas, T₁ = 400 K
The final temperature of the gas, T₂ = 273 K
The initial pressure of the gas, P₁ = 0.40 atm
The final pressure of the given gas can be calculated from Gay Lussac's law as:
P₂ = (0.40/400) ×273
P₂ = 0.273 atm
Therefore, the pressure of this gas at 273 K is 0.273 atm.
Learn more about Gay Lussac's law, here:
#SPJ2
Answer:
The volume of the object = 0.0203 m³
Explanation:
From Archimedes principle,
Upthrust = lost in weight = amount of water displaced.
U = W₁ - W₂
Where U = upthrust, W₁ = Weight in air, W₂ = weight in water.
U = 930- 731
U = 199 N.
but mass of water displaced,
m = U/g where g = 9.8 m/s²
m = 199/9.8
m = 20.31 kg.
Recall,
Density = mass/volume.
Density of water = mass of water displaced/ volume of water displaced
D = m/V
V = m/D......................................... Equation 1
Where V = volume of water displaced, m = 20.31 kg, D = 1000 kg/m³
Substitute into equation 1
V = 20.31/1000
V = 0.0203 m³
the volume of water displaced = 0.0203 m³
Note: That when an object is immersed in water, the volume of water it displaced is equal to it's volume.
Hence, Volume of water displaced = volume of the object.
Hence the volume of the object = 0.0203 m³
B. meniscusity.
C. viscosity.
D. capillarity.
the correct answer is
B. Infrared waves
C. X rays
D. Ultraviolet rays
Answer:
D. Ultraviolet rays
Explanation: