There are 5.78 × 10^20 sulfide ions in sodium sulfide
The formula of the compound is Na2S. The molar mass of the compound is calculated as follows; 2(23) +32 = 46 + 32 = 78 g/mol
Number of moles of Na2S = 0.15 g/ 78 g/mol = 0.0019 moles
Since there is 1 mole of Na^+ and 2 moles of S^2- in Na2S, the number of S^2- ions in 0.19 moles of Na2S is 0.00096 moles of S^2-.
If 1 mole of S^2- contains 6.02 × 10^23
0.095 moles of S^2- contains 0.00096 moles × 6.02 × 10^23/ 1 mole
= 5.78 × 10^20 sulfide ions
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Answer:
pOH= 11
Explanation:
pOH= -log[10^ -11]= 11
Consider the titration of a 17.2 mL sample of 0.128 M HC2H3O2 with 0.155 M NaOH. Ka(HC2H3O2) = 1.8x10-5 Determine the pH at 0.46 mL of added base.
Answer:
1. pH = 2,82
2. 3,20mL of 1,135M NaOH
3. pH = 3,25
Explanation:
The buffer of acetic acid (HC₂H₃O₂) is:
HC₂H₃O₂ ⇄ H⁺ + C₂H₃O₂⁻
The reaction of HC₂H₃O₂ with NaOH produce:
HC₂H₃O₂ + NaOH → C₂H₃O₂⁻ + Na⁺ + H₂O
And ka is defined as:
ka = [H⁺] [C₂H₃O₂⁻] / [HC₂H₃O₂] = 1,8x10⁻⁵ (1)
1. When in the solution you have just 0,13M HC₂H₃O₂ the concentrations in equilibrium will be:
[H⁺] = x
[C₂H₃O₂⁻] = x
[HC₂H₃O₂] = 0,13 - x
Replacing in (1)
[x] [x] / [0,13-x] = 1,8x10⁻⁵
x² = 2,34x10⁻⁶ - 1,8x10⁻⁵x
x² - 2,34x10⁻⁶ + 1,8x10⁻⁵x = 0
Solving for x:
x = - 0,0015 (Wrong answer, there is no negative concentrations)
x = 0,0015
As [H⁺] = x = 0,0015 and pH is -log [H⁺], pH of the solution is 2,82
2. The equivalence point is reached when moles of HC₂H₃O₂ are equal to moles of NaOH. Moles of HC₂H₃O₂ are:
0,0466L × (0,078mol / L) = 3,63x10⁻³ moles of HC₂H₃O₂
In a 1,135M NaOH, these moles are reached with the addition of:
3,63x10⁻³ moles × (L / 1,135mol) = 3,20x10⁻³L = 3,20mL of 1,135M NaOH
3. The initial moles of HC₂H₃O₂ are:
0,0172L × (0,128mol / L) = 2,20x10⁻³ moles of HC₂H₃O₂
As the addition of NaOH spent HC₂H₃O₂ producing C₂H₃O₂⁻. Moles of C₂H₃O₂⁻ are equal to moles of NaOH and moles of HC₂H₃O₂ are initial moles - moles of NaOH. That means:
0,46x10⁻³L NaOH × (0,155mol / L) = 7,13x10⁻⁵ moles of NaOH ≡ moles of C₂H₃O₂⁻
Final moles of HC₂H₃O₂ are:
2,20x10⁻³ - 7,13x10⁻⁵ = 2,2187x10⁻³ moles of HC₂H₃O₂
Using Henderson-Hasselbalch formula:
pH = pka + log₁₀ [C₂H₃O₂⁻] / [HC₂H₃O₂]
Where pka is -log ka = 4,74. Replacing:
pH = 4,74 + log₁₀ [7,13x10⁻⁵] / [2,2187x10⁻³ ]
pH = 3,25
I hope it helps!
The stability of an atom is affected by the balance between the electrons, protons, and neutrons in an atom.
A particle less than an atom is referred to as a subatomic particle. A subatomic particle can either be an elementary particle, which is not made of other particles, or a composite particle, which is composed of other particles, according to the Standard Model of particle physics.
Particles smaller than an atom are referred to as subatomic particles. The three primary subatomic particles present in an atom are protons, neutrons, and electrons.
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Answer : The volume required to fill the gas tank is, 45.42 liters
Explanation :
Conversion used for gallon to liters are:
As we are given the volume of gas tank in gallon is, 12.0 gal
Now we have to determine the volume of gas tank in liters.
As, 1 gallon = 3.785 liter
So, 12.0 gallon =
Therefore, the volume required to fill the gas tank is, 45.42 liters
Answer:
Lewis structure of Hydronium ion is shown below :
Explanation:
Lewis structure : It is a representation of valence electrons on the atoms in a molecule
Here , Hydronium ion is given , which contains 1 atom of oxygen and 3 atoms of hydrogen .
Oxygen has a total of 6 valence electrons and hydrogen contains 1 valence electron .
Oxygen share its 3 valence electrons with 3 hydrogen atoms and left with 3 valence electrons. From these three valence electrons of oxygen atom two electrons will be shown as a pair of electrons on oxygen atom but a single electron can not be shown . So , to simplify this, one positive charge is shown overall .
Resonance structure will be same as the hybrid structure because all three atoms are same , that is hydrogen .