g The electronic structure of which ONE of the following species cannot be adequately described by a single Lewis formula? (In other words, the electronic structure of which one can only be described by drawing two or more resonance structures?) A) C2H4 B) SO3 2– C) SO3 D) C3H8 E) HCN

Answers

Answer 1
Answer:

Answer:

C) SO3

Explanation:

Lewis formula shows the bonding between atoms of a molecule and expresses the lone pair present in the atoms.

SO3 or Sulfur trioxide cannot be adequately described by a single Lewis formula because it has majorly 3 resonance structures because Sulfur does not follow the octet rule and can expand electrons in its outer shell.

Hence, the correct answer is C) SO3

Answer 2
Answer:

Final answer:

SO3, or Sulfur Trioxide, is the molecule whose electronic structure requires the depiction of multiple resonance structures for adequate description. The rest of the species can be represented with a single Lewis structure.

Explanation:

The electronic structure that can only be described by drawing two or more resonance structures is SO3 (Sulfur Trioxide). This molecule has 24 valence electrons having a central atom with expanded octet. The Lewis structure is drawn in a way that three resonance structures are needed to represent the bonding in this molecule adequately. On the other hand, the rest of the species given in the options can be described using a single Lewis formula.

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You have 0.500 L of an 0.250 M acetate buffer solution (i.e. [HC₂H₃O₂] + [C₂H₃O₂⁻] = 0.250 M) at pH 3.50. How many mL of 1.000 M NaOH must you add in order to change the pH to 5.07? Acetic acid has a pKa of 4.74.

Answers

Answer:

80mL of 1.00M NaOH

Explanation:

Using H-H equation, we can determine oH of a buffer as acetate buffer. First, we need to determine amount of acetate ion and acetic acid at pH 3.50 and 5.07. Then, with the reaction of NaOH with acetic acid we can find the amount of 1.00M NaOH that must be added:

At pH 3.50:

pH = pka + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

3.50 = 4.74 + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

0.057544 = [C₂H₃O₂⁻] / [HC₂H₃O₂] (1)

Using and replacing in (1):

[HC₂H₃O₂] + [C₂H₃O₂⁻] = 0.250 M

[HC₂H₃O₂] + 0.057544[HC₂H₃O₂] = 0.250 M

1.057544 [HC₂H₃O₂] = 0.250M

[HC₂H₃O₂] = 0.2364M * 0.500L = 0.1182 moles of acetic acid at first pH

At pH 5.07:

pH = pka + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

5.07 = 4.74 + log [C₂H₃O₂⁻] / [HC₂H₃O₂]

2.13796= [C₂H₃O₂⁻] / [HC₂H₃O₂] (1)

Using and replacing in (1):

[HC₂H₃O₂] + 2.13796[HC₂H₃O₂] = 0.250 M

3.13796 [HC₂H₃O₂] = 0.250M

[HC₂H₃O₂] = 0.07967M * 0.500L = 0.0398 moles of acetic acid at first pH

Now, NaOH reacts with HC₂H₃O₂ as follows:

NaOH + HC₂H₃O₂ → NaC₂H₃O₂ + H₂O

As moles of acetic acid decreases from 0,1198 moles - 0,0398 moles = 0,08 moles of acetic acid are consumed = 0,08 moles of NaOH

0,08 mol NaOH * (1L / 1mol) = 0,08L of 1.00M NaOH =

80mL of 1.00M NaOH

A chemist titrates 90.0 mL of a 0.5870 M acetic acid (HCH, CO) solution with 0.4794M NaOH solution at 25 °C. Calculate the pH at equivalence. The p Kg of acetic acid is 4.76. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added

Answers

Answer:

9.09

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

Is the law of conservative mass observed in this equation CaCO3 + 2HCI -->CaCI2 +H2O + CO2

Answers

Answer:

The law is observed in the given equation.

Explanation:

CaCO₃ + 2HCI → CaCI₂ +H₂O + CO₂

In order to find out if the law of conservative mass is followed, we need to count how many atoms of each element are there in both sides of the equation:

  • Ca ⇒ 1 on the left, 1 on the right.
  • C ⇒ 1 on the left, 1 on the right.
  • O ⇒ 3 on the left, 3 on the right.
  • H ⇒ 2 on the left, 2 on the right.
  • Cl ⇒ 2 on the left, 2 on the right.

As the numbers for all elements involved are the same, the law is observed in the given equation.

Compound X has the formula C8H14.X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane. Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Answers

Answer:

Compound X has the formula C8H14.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethyl cyclohexane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Explanation:

The degree of unsaturation in the given molecule C8H14 is:

DU=(Cn+1)-Hn/2-Xn/2+Nn/2

where,

Cn=number of carbon atoms

Hn=number of hydrogen atoms

Xn=number of halogen atoms

Nn=number of nitrogen atoms

C8H14:

DU=(8+1)-14/2

=>DU=9-7 =2

Hence, the given molecule will have either two double bonds or one double bond and one ring or two rings.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane.

This indicates that the molecule X has one double bond and one ring that is cyclohexane ring.

Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O).

So, the molecule has a ring and double bond CH2.

Based on the given data the structure of compound X is shown below:

The reaction sequence is shown below:

Final answer:

Compound X, with the formula C8H14, reacts with hydrogen to form 1,2-dimethylcyclohexane. When treated with ozone and zinc, it yields a ketone and formaldehyde. Therefore, the structure of X is 1,2-dimethylcyclohexane.

Explanation:

X is a compound with the formula C8H14. The reaction of X with hydrogen in the presence of a palladium catalyst produces a mixture of cis- and trans-1,2-dimethylcyclohexane. When X is treated with ozone followed by zinc in aqueous acid, it forms a ketone and formaldehyde (CH2=O).

This information tells us that compound X is a cycloalkane with two methyl groups. Since it reacts with hydrogen to form 1,2-dimethylcyclohexane, we know that X must have a cyclohexane ring with two methyl groups at the 1 and 2 positions. The cis and trans isomers of 1,2-dimethylcyclohexane have different arrangements of the methyl groups relative to each other.

Thus, the structure of compound X is 1,2-dimethylcyclohexane.

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Which factor is likely to impact the possible number of compounds?

Answers

Answer:

The correct answer is the tendency of all the elements to react with every other element.  

Explanation:

A component in which two or more elements are bonded chemically leads to the production of a compound. A compound refers to a pure component as it comprises elements that are in their pure state. The formation of a compound takes place when the elements react with each other based upon their reactivity.  

For example, the element chlorine is deficient of one electron and the element sodium exhibits one additional electron. Thus, chlorine easily reacts with the sodium in order to obtain stability. Therefore, the formation of sodium chloride takes place. Hence, it can be concluded that the tendency of all the elements to react with every other element is the condition, which is possible to influence the probable number of compounds.

the impact of possible number of compounds is the ability of all elements to react with every other atoms

How many molecules are shown in the chemical formula pictured? H3PO4A) 1
B) 3
C) 4
D) 7

Answers

Answer

A(1)

Explanation:

If you don't see a coefficient, which is the big number in front of the formula, then it's only one molecule.

Example of coefficient

4H3PO4