Answer:
D and E
Explanation:
D. PCl3
E. CH2Cl2
Answer:
ΔHrxn = 193107.69 J/mol
Explanation:
ΔHrxn = mcΔT
m = mass
c = heat capacity
ΔT = temperature variation
density = m/V
m = density x V
m = 1.00 g/mL x 400.0 mL
m = 400.0 g
ΔHrxn = mcΔT
ΔHrxn = 400 g x 4.184 J/g°C x 6.00 °C
ΔHrxn = 10041.6 J
CaO + 2HCl → CaCl₂ + H₂O
CaO = 56.0774 g/mol
2.90 g CaO = 0.052 mol
400.0 mL of 1.500 mol/L HCl = 0.6 mol HCl
ΔHrxn = 10041.6 J is for 0.052 mol of CaO
ΔHrxn = 193107.69 J is for 1 mol of CaO
Answer:- 1500 calories
Solution:- mass of bear = 1.850 g
volume of water = 100.0 mL
Density of water is 1.00 g/moL. So, mass of water would be 100.0 g.
delta T for water = 15.0 degree C
specific heat capacity for water is 1 cal/(g* degree C)
q = m x c x delta T
where, q is the heat energy, m is mass, c is specific heat capacity and delta T is change in temperature.
for water, q = 100.0 x 1 x 15.0
q = 1500 calorie
heat gained by water = heat lost by bear
So, the 1.850 g bear has 1500 cal or 1.50 Cal.
(Where, 1 Cal = 1000 cal)
Answer:
propane
Explanation:
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Answer:
Methoxyethane also known as ethyl methyl ether
Answer:
In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.
Explanation: