Solve the following problem:

Answers

Answer 1

Answer:

Answer:

$n^(8)$

Step-by-step explanation:

Given the Quotient Rule of Exponents: $(a^(m))/(a^(n)) = a^((m-n))$ , you must subtract the exponents of each exponential expression (in fractions) before applying the Product Rule of Exponents (I will explain in a while what it means).

First, subtract the exponents of the first fraction, $(n^(5))/(n^(3)) = n^((5 - 3)) = n^(2)$

Next, subtract the exponents of the second fraction: $(n^(9))/(n^(3)) = n^((9 - 3)) = n^(6)$

At this point, we have the following exponential expressions: $n^(2)$ and $n^(6)$ .

Since the required operation is multiplication, then you can apply the Product Rule of Exponents: $a^(m) a^(n) = a^((m+n))$

$n^(2)*n^(6) = n^((2+6)) = n^(8)$

Therefore, the correct answer is $n^(8)$ .

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A new DVD is available for sale in a store one week after its release. The cumulative revenue, $R, from sales of the DVD in this store in week t after its release is R=f(t)=350 ln tR=f(t)=350lnt with t>1. Find f(5), f'(5), and the relative rate of change f'/f at t=5. Interpret your answers in terms of revenue.

Answers

Solution :

It is given that :

$f'(t) = (350 \ln t)'$

$=350(\ln t)'$

$=(350)/(t)$

So, $f(5)=350 \ln (5) \approx 563$

$f'(5) = (350)/(5)$

$=70$

The relative change is then,

$(f'(5))/(f(5))=(70)/(350\ \ln(5))$

$=(1)/(5\ \ln(5))$

$\approx 0.12$

$=12\%$

This means that after 5 weeks, the revenue from the DVD sales in $563 with a rate of change of $70 per week and the increasing at a continuous rate of 12% per week.

Calculate S37 for the arithmetic sequence in which a7 = 25 and the common difference is d=-1.7

Answers

The value of 37th term of the arithmetic sequence will be;

⇒ - 26

What is Arithmetic sequence?

An arithmetic sequence is the sequence of numbers where each consecutive numbers have same difference.

Given that;

The values are,

⇒ a₇ = 25

And, The common difference is d = -1.7

Now,

Since, The nth term of arithmetic sequence is;

⇒ a(n) = a + (n - 1)d

And, ⇒ a₇ = 25

So, We get;

⇒ a₇ = a + (7 - 1) (- 1.7)

⇒ 25 = a + 6 × - 1.7

⇒ 25 = a - 10.2

⇒ 25 + 10.2 = a

⇒ a = 35.2

So, The 37th term of the arithmetic sequence is;

⇒ a₃₇ = 35.2 + (37 - 1) (- 1.7)

⇒ a₃₇ = 35.2 + 36 × - 1.7

⇒ a₃₇ = 35.2 - 61.2

⇒ a₃₇ = - 26

Thus, The value of 37th term of the arithmetic sequence will be;

⇒ - 26

Learn more about the arithmetic sequence visit|:

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Answer:

-26

Step-by-step explanation:

25 is a7. if you subtract 1.7 each time then at 37 the number will be -26.

What's the answer for p2 when p=25

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Answer is 625
Hope it helps :)

Answer: p^2 = 25 ^2 = 625

A product p and six is wrtten as

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Answer: 6p

Explanation: The word "product" is a

keyword that tells us to use multiplication.

So your answer can be written as 6 · p or just 6p.

Don't write your answer as p6.

Even though it's technically correct, I would always put

the number before the variable as a matter of form.

Answer:

Step-by-step explanation:

Help please it due today thank u

Answers

Answer:

Step-by-step explanation:

y=4x+30

Answer: y = 30x + 4 (/1)

Step-by-step explanation:

30 is the y intercept because it says its' the startup fee. Therefore it must be the y intercept.

4 must be the gradient. Basically, on a Cartesian plane, the y intercept will be on 30. Move 4 digits up and 1 to the left continually

How would you write 0.7 repeated as a fraction

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0.7 repeated can be written as a fraction $(7)/(9)$ .

What are Fractions?

Fractions are defined as a part or portion in a whole. There are two parts for a fraction, numerator which is the upper part and the denominator, which is the lower part.

Fractions are generally written in the form $(p)/(q)$ , where p and q are real numbers. Here, the number p is called the numerator and the number q is called the denominator.