Answer:
(x-8) (x+7)
Step-by-step explanation:
x^2 -x-56
We want to factor this problem.
What two numbers multiply to negative 56 and add to -1
-8 *7 = -56
-8+7 = -1
We can use -8 and 7
(x-8) (x+7)
Check:
FOIL
first: x*x =x^2
outer: 7x
inner:-8x
last: -8*7 = -56
Add this together
x^2 +7x-8x -56 = x^2 -x-56
Answer:
c+2
Step-by-step explanation:
Distribute the Negative Sign:
=9c2+3c+9+−1(9c2+2c+7)
=9c2+3c+9+−1(9c2)+−1(2c)+(−1)(7)
=9c2+3c+9+−9c2+−2c+−7
Combine Like Terms:
=9c2+3c+9+−9c2+−2c+−7
=(9c2+−9c2)+(3c+−2c)+(9+−7)
Answer:
c + 2
Step-by-step explanation:
(9c² + 3c + 9) - (9c² + 2c + 7)
9c² + 3c + 9 - 9c² - 2c - 7
9c² + 3c + 9 - 9c² - 2c - 7
c + 2
Answer:
$15,000
Step-by-step explanation:
The $1500 interest on a home equity loan used for purposes other than home improvement is not deductible with other home loan interest as an itemized deduction.
However, the interest on a loan for qualified educational expenses may be considered an adjustment to income, within limits.
Only the $15,000 main mortgage interest can be an itemized deduction.
The total possible mortgage interest deduction for Mark in this scenario is $16,500. However, the actual amount he can deduct depends on his adjusted gross income and whether his itemized deductions exceed the standard deduction.
Under US tax law, taxpayers can deduct the interest on home mortgages and home equity loans, subject to some limitations. The interest expense on the main mortgage ($15,000) and the interest expense on the home equity loan ($1,500) can be combined for a total interest deduction of $16,500. However, the deduction may not be the full amount if there are other factors that would limit the amount of itemized deductions that Mark can claim. This can depend on his adjusted gross income and whether the total of his itemized deductions exceeds the standard deduction. It's also worth noting that the tax benefits of home ownership, such as the mortgage interest deduction, is a key reason why many people choose to buy rather than rent, as it can lead to significant financial savings.
#SPJ3
Answer:
x= and
Step-by-step explanation:
(x - 5)^(2) +3(x-5)+9
(x - 5)^(2)= x2−10x+25
3(x-5)= 3x-15
x^2-10x+25+3x-15+9
x^2-7x+19=0
a=1 b=-7 c=19
use quadratic formula
Answer:
width=25/3
Length=75/3
Step-by-step explanation:
Given
Perimeter=50
Let width=x
Length=4x
So perimeter =2(length+width)
2(length+width)=50
2(X+2x)=50
3x=25
X=25/3
So width=25/3
Length=75/3
25 atmospheres in a volume of 120 liters. Find the pressure if the volume is decreased to 110
liters and the temperature is increased to 335 degrees Kelvin.
Hint: Look at the equation V = k* Then use the initial values to solve for k. Then plug in the
values you know for the second set of values and solve for your unknown.
Answer:
Pressure=22.55 atmospheres
Step-by-step explanation:
Let
V=volume of the ideal gas
P=pressure
T=temperature
Volume varies directly with temperature and inversely with pressure
V=kT/P
t=320°K
P=25 atmospheres
V=120 liters
V=kT/P
120=k*320/25
120=320k/25
120×25=320k
3000=320k
k=300/320
=9.375
k=9.375
V=110 liters
p=?
t=335°K
V=kT/P
110=9.375*335/p
110=3,140.625/p
110p=3,140.625
P=3,140.625/110
=28.55
P=22.55 atmospheres