1. Select all the sums that are positive.0-5+(-2)
0 5+(-2)
0-3+4
O 0+(-3)
-2-(-4)
ILL MARK BRAINLY

Answers

Answer 1

Answer:

Answer:

the 2nd, 3rd, and 5th are your positive sums

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Solve the system by graphing. Write the solution as an ordered pair. y = 1/3x + 2 y = –x – 2Help me please....I need good grades

Answers

ANSWER

The solution is where the two graphs intersect, which is
$(-3,1).$

EXPLANATION

The given system of equations are
$y = (1)/(3) x + 2$
and

$y = - x - 2$

We need to graph the two equations.

Let us graph

$y = (1)/(3) x + 2$
first.

We need at least two points.

You can choose any appropriate value for x and solve for y. Choosing zero makes our working easier. So let us plot the intercepts.

When
$x = 0$

$\Rightarrow \: y = (1)/(3) (0) + 2$

$\Rightarrow y = 0 + 2$

$\Rightarrow y = 2$

So this gives us the ordered pair,

$(0,2)$

When
$y = 0$
we get,

$0= (1)/(3) x + 2$

$\Rightarrow \: - 2 = (1)/(3) x$

$\Rightarrow \: - 2 * 3= x$

$\Rightarrow \: -6= x$
This also gives the ordered pair

$(-6,0).$

We plot these two points and draw a straight line through them to obtain the blue graph in the attachment.

For the second line

We again find the intercepts and plot them.

When
$x = 0$

$y = - 0 - 2$

$\Rightarrow \: y = - 2$

This gives the ordered pair

$(0,-2)$

Also, when
$y = 0$

then we have,

$0 = - x - 2$

$2 = - x$

$x = - 2$

Then we again have the ordered pair,

$(-2,0)$

We plot these two points on the same graph sheet to obtain the red graph above.

The intersection of the two lines is
$(-3,1)$

You will get good grades so don't worry much.

Answer:

jh24

Step-by-step explanation:

2k + 5 — 7k = 8 + 3

I need someone to help me out with this one please.

Answers

2k + 5 - 7k = 8+3
-5k + 5 = 11
-5k = 6
k= -6/5

Answer:

-1.2

Step-by-step explanation:

2k+5-7k=8+3

2k-7k+5=11

-5k=11-5

-5k=6

-5k/5=6/5

k=-1.2

Find the 15th term in the geometric sequence below.20, 10, 5, 2.5, . . .
A.-25/4,096

B.-5/4,096

C.5/4,096

D.25/4,096

Answers

geo sequence
$a_n=a_1r^(n-1)$
an=nth term
a1=first term
r=common ratio
n=which term

10/20=1/2
r=1/2
20=a1

$a_(15)=20(1/2)^(15-1)$ =
$a_(15)=20(1/2)^(14)$ =
$a_(15)=20( (1)/(16384) )$ =
$a_(15)= (20)/(16384)$ =
$a_(15)= (5)/(4096)$

C is answer

Which choice is equivalent to the quotient shown here when x > 0?√72x^3 divide by square root of 50x^2