What will be the next digit in the sentence 1, 1, 2, 3, 5, 8, 13, 21, 34?Please show me your way of thinking :)

Answers

Answer 1

Answer: $This\ is\ a\ Fibonacci\ sequence:\n1;\ 1;\ 2;\ 3;\ 5;\ 8;\ 13;\ 21;\ 34;...\n\na_1=1\na_2=1\na_3=a_1+a_2=1+1=2\na_4=a_2+a_3=1+2=3\na_5=a_3+a_4=2+3=5\na_6=a_4+a_5=3+5=8\na_7=a_5+a_6=5+8=13\na_8=a_6+a_7=8+13=21\na_9=a_7+a_8=13+21=34\na_(10)=a_8+a_9=21+34=55\na_(11)=a_9+a_(10)=34+55=89\na_(12)=a_(10)+a_(11)=55+89=144\n\vdots$

$a_n=a_(n-2)+a_(n-1)$ -The next number is the sum of the previous two.

Answer 2

Answer: It's Fibonacci :

so you have
1, 1, 2, 3, 5, 8, 13, 21, 34, 55

Basically, to find out the number:

13=5+8
21=13+8
34=21+13
55=34+21

The next number is the sum of the previous two.

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Six boxes of crackers cost $18. At this
price, how much do 15 boxes cost?

Answers

Answer:

6x3=18 and 15x3= 45 so 45 is the answer.

Step-by-step explanation:

Answer:

Step-by-step explanation:

18 divided by 6 is 3. and 3 times 15 is 45. And to check it do 45 divided by 15 and you get 3. so 45 is the answer.

Write the missing value above the variable. M-9=7

Answers

If you're for the value of "m" then follow these steps to see what the answer is

m - 9 - 7 = ?
? = 0

Now, let's add the number 16 to the sides that you're working with
Here's what I am talking about in case you don't know what I am talking
m - 16 = 0
+ 16
-------
16

So, the value of m is 16 ;
$m=16$

This is basic mathematics.Just practice your addition and subtraction facts in the problem like this

m=16
16-9=7
hope this helped:)

Jo Bower owns 150 shares of Data General stock. She purchased the stock for $24 a share. She sold her stock for $30 a share. The commissions required to buy and sell her stock totaled $120. Assuming that she received no dividends during the time she owned the stock, what is her total return for this transaction? A. $600 B. $780 C. $900 D. $2,400

Answers

Her expenses:
($24 x 150) + $120 = $3,600 + $120 = $3,720
Her profit:
$30 x 150 = $4,500
Total profit:
$4,500 - $3,720 = $780
Answer: B ) $780

Answer:

$780.

Step-by-step explanation:

Jo Bower owns 150 shares of Data General stock.

She purchased the stock for $24 a share.

So, cost of purchasing 150 shares = $150* 24$

= $3600$

She sold her stock for $30 a share.

So. she sold 150 shares of amount = $150* 30$

= $4500$

So, Profit = SP-CP

Profit = $4500-$3600

Profit = $900

The commissions required to buy and sell her stock totaled $120.

So, her total return for this transaction = 900-120

=780

Hence, Her total return for this transaction is $780.

Express Fx and Fy in terms of the length of the vector F and the angle θ, with the components separated by a comma.

Answers

Fx, Fy = F cos θ, F sin θ

Further explanation

This is a fundamental problem with vector components.

A vector quantity is some quantities that have the magnitude and a direction. For example, all forces or momentums are vectors.
Whereas, a scalar quantity only has magnitude. For example, all forms of energy are scalars.

The list below shows some recognized methods to represent a vector. i.e., a force.

$\boxed{ \ \textit{\textbf{F}}, \vec{F}, \bar{F} \ }$

It is possible to split one vector into two vectors. This process is called resolving and the vectors that we get are called the components of the original vector.

Vector problems can always be solved by using the mathematics of trigonometry, i.e., the functions of sine or cosine. This is particularly appropriate when resolving.

By using the cartesian coordinate system, see the attachment on how to calculate the values of either these components.

Horizontal component: $\boxed{ \ F_x = \textit{\textbf{F}}\ cos \ \theta \ }$
Vertical component: $\boxed{ \ F_y = \textit{\textbf{F}} \ sin \ \theta \ }$

Here, the angle between the vector F and the horizontal axis we call θ (theta).

As a reminder:

$\boxed{cos \ \theta = (adjacent)/(hypotenuse)} \rightarrow cos \ \theta = (F_x)/(F) \rightarrow \boxed{F_x = F cos \ \theta}$
$\boxed{sin \ \theta = (opposite)/(hypotenuse)} \rightarrow sin \ \theta = (F_y)/(F) \rightarrow \boxed{F_y = F sin \ \theta}$

Learn more

Finding the acceleration between two vectors brainly.com/question/6268248
A correct representation of 0.000025 in scientific notation brainly.com/question/2261308
The theoretical density of platinum which has the FCC crystal structure brainly.com/question/5048216

Keywords: express Fx and Fy, in terms of the length of the vector F, and the angle θ, with the components, separated by a comma, resolving, split, horizontal, vertical, angle, theta, sine, cosine, trigonometry, cartesian coordinate system

The components of the vector F are $\fbox{\begin\nF\cos\theta\end{minispace}}$ and $\fbox{\begin\nF\sin\theta\end{minispace}}$ .

Further Explanation:

A physical quantity can be defined as the physical property that can be measured and have some value in numbers.

For example- mass, amount of substance, length, time, electric current, temperature, force, light intensity, density, velocity, speed etc.

A quantity is said as a vector if it has some magnitude and direction in order to give the details regarding the quantity.

For example- Force, velocity, current density, electric field, magnetic field, displacement, acceleration, momentum etc.

A quantity is said as a scalar if it has only the magnitude in order to give the details regarding the quantity.

For example- speed, distance, current, volume, density, mass, energy, time, temperature etc.

Given:

The resultant vector is $F$ .

The horizontal component is ${\vec F_x}$ .

The vertical component is ${\vec F_y}$ .

Concept:

Let a vector have some length $F$ and making an angle $\theta$ with horizontal axis.

The triangle rule of resultant vector state that when two vector is denoted by the two sides of the triangle and the magnitude and the direction is taken in the same direction then the third side of the triangle denoted by resultant vector with some magnitude and direction.

The diagram is drawn as shown in the Figure 1.

The vertical component is along y-axis and the vertical component of the vector $\vec F$ is expressed as: