MATHEMATICS COLLEGE

Question 9 of 10
Which inequality is shown in this graph?
Question 9 of 10 Which inequality is shown in this - 1

Answers

Answer 1
Answer:

Answer:

c

Step-by-step explanation:

the line is going down so we know it has to be a negative slope narrowing the answer choices down to a and c but when you pick a point to check for the reigon (i used 0,0 as a basic point) only c satisfies the inequality while keeping the point , not a.

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A community is deciding whether to find a new gymnasium

Answers

Whats the question ELAISSAROYER22

Consider a colony of E.Coli bacteria that is growing exponentially. A microbiologist finds that, initially, 1,000 bacteria are present and 50 minutes later there are 10,000 bacteria. a) Find expression for the number of bacteria Q(t) after t minutes. b) When will there be 1,000,000 bacteria?

Answers

Answer:

a)Q(t)=Q_(0)e^((ln10/50)t)

b) 150min

Step-by-step explanation:

a) Using the formula for colony growth Q(t)=Q_(0)e^(kt) we need to find the specific value of k, to do this you'll use the time, initial and final number of colonies provided in your problem.

Q(t)=Q_(0)e^(kt)\n\n10000=1000e^(k(50)) \n\n(10000)/(1000)=e^(50k) \n\n10=e^(50k)\n ln(10=e^(50k))\n\nln10=50k\n\nk=ln10/50\n\nQ(t)=Q_(0)e^((ln10/50)t)\n\n

b) Once we have our expression we only have to use our final and initial number of bacteria to find t.

Q(t)=Q_(0)e^((ln10/50)t)\n\n\n1000000=1000e^(0.046t)\n 1000=e^(0.046t)\nln( 1000=e^(0.046t))\nln1000=0.046t\nt=ln1000/0.046\nt=150 minutes

I hope you find this information useful! good luck!

Suppose the results indicate that the null hypothesis should be rejected; thus, it is possible that a type I error has been committed. Given the type of error made in this situation, what could researchers do to reduce the risk of this error? Increase the sample size. Choose a 0.01 significance level instead of a 0.05 significance level.

Answers

Answer:

You need to Choose a 0.01 significance level , instead of 0.05 significance level.

Step-by-step explanation:

Consider the provided information.

It is given that type I error has been committed.

Type I error occur, if we rejected the null hypothesis even null hypothesis is true.

We reject the null hypothesis if p-value < α

Accept the null hypothesis if p-value ≥ α

According to given condition the value of α is 0.05  that means 95% chance that your assumption is correct and 5% chance that assumption is wrong.

In order to reduce the risk of this error you need to increase the significance level so that the value of α becomes lower than the p value.

lower α means you will be less likely to detect a true difference if one really exists.

Hence, you need to Choose a 0.01 significance level , instead of 0.05 significance level.

Find the area of the triangle Please help

Answers

Answer:

14m^2

Step-by-step explanation:

Area of a triangle is - 1/2 base times hight

two triangels find the srea of both and add them

4x4x1/2 = 16x1/2 = 8m

3x4x1/2 = 12x1/2 = 6m

6m + 8m = 14m

You have also set up a card game in which a player picks a card from a standard deck of 52 cards. The player wins if these two events occur together: E1, in which the card drawn is a black card, and E2, in which the card drawn is a numbered card, 2 through 10.What is the probability of getting a black card and a numbered card? Calculate the probabilities P(E1) and P(E2) as fractions.

Answers

n (S) = 5\n n (E_1) = 2 x 13 = 26\nP (E_1) (n (E_1))/(n (S)) = \frac {26}{52} = (1)/(2) \n\n n (E_2) 4 x 9 = 36\nP (E_2)(n (E_2))/(n (S))=(36)/(52)= (9)/(13)

EDMENTUM / PLATO ANSWER!!!!!!!!

CAN JUST WRITE:

P (E_1) (n (E_1))/(n (S)) = \frac {26}{52} = (1)/(2) =  (50%)

P (E_2)(n (E_2))/(n (S))=(36)/(52)= (9)/(13) =  (69.2%) :)))))

First, let's count:

there are 26 possible outcomes for E1 (black card)

there are 4x9 = 36 possible outcomes for E2, to pick a numbered card (any color)

there are 2x9 =18 possible outcomes for E1 (black) AND E2 (numbered, spade + clower)

the probability of E1 AND E2 is the ratio of the count of possible outcomes for E1 + E2 and the count of all possible outcomes (52 choices to pick a card from the deck):

P(E1 and E2) = 18/52 (34.6%)

And as asked:

P(E1) = 26/52 = 1/2 (50%)

P(E2) = 36/52 = 9/13 (69.2%)

the temperature at 6pm was 72 degrees. this was 8 degrees cooler than at 4pm. the temperature at 10am wss 5 degrees hotter than at 4pm. what was the temperature 10am

Answers

The temperature at 10 am was 5° +8° = 13° hotter than the 72° temperature at 6 pm.

The temperature at 10 am was 72° +13° = 85°.
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