Which is the positive slope m, where m<1
Which is the positive slope m, where m&lt;1 - 1

Answers

Answer 1
Answer:

Answer:

Line D

Step-by-step explanation:

Slope of a line passing through (x_1,y_1) and (x_2,y_2) is given by,

m = (y_2,y_1)/(x_2-x_1)

Slope of line A passing through (-6, 3) and (0, 0)

m = (3-0)/(-6-0)=-(1)/(2)

Negative and m < 1

Slope of line B passing through (-2, 4) and (0, 0)

m = (4-0)/(-2-0)=-2

Negative and m < 1

Slope of line C passing through origin and (2, 5),

m = (5-0)/(2-0) = 2.5

Positive and m > 1

Slope of line D passing through origin and (3, 2)

m = (2-0)/(3-0)=(2)/(3)

Positive but m < 1

Therefore, Line D will be the answer.


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Answers

Answer:

Step-by-step explanation:

The method applied in this scenario is called simple random sampling. A sample of 100 customers is chosen from a larger population of customers and each customer has the same chance of being selected for the survey at any given time. Also, the chance of selecting 100 customers from each store is the same during the sampling process. The order of sampling at each store does not follow a certain order, thus, It is different from systematic random sampling.

Kristl has saved 30%of her tuition for
dance class. She
needs to have $600
save. How much has
she saved so far?

Answers

Answer:

$180

Step-by-step explanation:

there are four pizzas which each have 12 slices. these pizzas will be divided between 15 people. how many slices does each person get if they are split evenly

Answers

Answer:

3.2 so they would each get around 3 slices!

Answer:

3.2

Step-by-step explanation:

so 3 slices for each

A men and a women decided to meet at a certain location. If each of them independently arrives at a time uniformly between 12pm and 1pm, find the probability that the first to arrive has to wait longer than 10 mins?

Answers

Answer:

the probability that the first to arrive has to wait longer than 10 mins is 35/36.

Step-by-step explanation:

First you need to denote by X and Y the time past 12 noon that the man and woman arrive.

Then you have to compute P(X+10<Y)+P(Y+10<X), which by symmetry equals 2P(X+10<Y).

So basically you have to compute P(X+10<Y).

check the attachment for the rest of the step by step.

Answer should be 25/72

But since we want 2× of the above probability 2× 25/72 = 25/36finalanswer.

Find each x-value at which f is discontinuous and for each x-value, determine whether f is continuous from the right, or from the left, or neither. f(x) = x + 4 if x < 0 ex if 0 ≤ x ≤ 1 8 − x if x > 1 x = (smaller value) continuous from the right continuous from the left neither

Answers

Using continuity concepts, it is found that the function is left-continuous at x = 1.

-------------------------------

A function f(x) is said to be continuous at x = a if:

\lim_(x \rightarrow a^(-)) f(x) = \lim_(x \rightarrow a^(+)) f(x) = f(a)

  • If only \lim_(x \rightarrow a^(-)) f(x) = f(a), the function is left-continuous.
  • If only \lim_(x \rightarrow a^(+)) f(x) = f(a), the function is right-continuous.

-------------------------------

The piece-wise definition of the function f(x) is:

x + 4, x < 0

x, 0 \leq x \leq 1

8 - x, x > 1

We have to check the continuity at the points in which the definitions change, that is, x = 0 and x = 1.

-------------------------------

At x = 0:

  • The definition at 0 is f(0) = 0
  • Approaching x = 0 from the left, we have values less than 0, thus:

\lim_(x \rightarrow 0^(-)) f(x) = \lim_(x \rightarrow 0) x + 4 = 0 + 4 = 0

  • Approaching x = 0 from the right, we have values greater than 0, thus:

\lim_(x \rightarrow 0^(+)) f(x) = \lim_(x \rightarrow 0) x = 0

Since the limits are equal, and also equal to the definition at the point, the function is continuous at x = 0.

-------------------------------

At x = 1:

  • The definition at 1 is f(1) = 1
  • Approaching x = 1 from the left, we have values less than 1, thus:

\lim_(x \rightarrow 1^(-)) f(x) = \lim_(x \rightarrow 1) x = 1

  • Approaching x = 1 from the right, we have values greater than 1, thus:

\lim_(x \rightarrow 1^(+)) f(x) = \lim_(x \rightarrow 1) 8 - x = 8 - 1 = 7

To the right, the limit is different, thus, the function is only left continuous at x = 1.

A similar problem is given at brainly.com/question/21447009

Answer:

the function is continuous from the left at x=1 and continuous from the right at x=0

Step-by-step explanation:

a function is continuous from the right , when

when x→a⁺ lim f(x)=f(a)

and from the left when

when x→a⁻ lim f(x)=f(a)

then since the functions presented are continuous , we have to look for discontinuities only when the functions change

for x=0

when x→0⁺ lim f(x)=lim  e^x = e^0 = 1

when x→0⁻ lim f(x)=lim  (x+4) = (0+4) = 4

then since f(0) = e^0=1 , the function is continuous from the right at x=0

for x=1

when x→1⁺ lim f(x)=lim  (8-x) = (8-0) = 8

when x→1⁻ lim f(x)=lim e^x = e^1 = e

then since f(1) = e^1=e , the function is continuous from the left at x=1

Please help fast, thanks.

Answers

I believe it is m < 5 I could be wrong sorry.