Answer:
-2x - 12
Step-by-step explanation:
-5(4x)+6(3x - 2)
-20x +18x - 12
-2x - 12
Answer:
$0.00
Step-by-step explanation:
$20.00-$20.00=$0.00
Answer:
Correct option: "No, a probability of about 0.20 would be assigned using the relative frequency method if selection is equally likely."
Step-by-step explanation:
The assumption made is that all the 5 different packages are equally likely, i.e. the probability of selecting a package is .
The probability distribution is shown below.
According to the probability distribution:
So it can be seen that the probability of preferring any of the 5 designs are not same.
Thus, the designs are not equally likely.
The correct option is "No, a probability of about 0.20 would be assigned using the relative frequency method if selection is equally likely."
The selection Probability determined using the relative frequency method do not match the assigned probabilities, suggesting that the data do not confirm the belief that one design is as likely to be selected as another.
The given data can be used to calculate the relative frequencies of each package design selected by the consumers.
To determine the selection probabilities using the relative frequency method, divide the number of times a design was preferred by the total number of consumers.
For example, for design 1, the selection probability would be 10/100 = 0.1.
Similarly, for design 2, the selection probability would be 5/100 = 0.05.
The selection probabilities for designs 3, 4, and 5 would be 0.3, 0.4, and 0.15 respectively.
Comparing these probabilities to the assigned probabilities, it can be observed that the assigned probabilities do not match the observed relative frequencies, indicating that the data do not confirm the belief that one design is just as likely to be selected as another.
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Answer:
(Choice A) A graph of an increasing linear function in quadrant 1 with a positive y-intercept.
Step-by-step explanation:
The weight of the sumo wrestler starts at a positive value of 79.5 kilograms, and we are given that the sumo wrestler gains a linear amount of weight per month at 5.5 kilograms per month.
If we were to graph this relationship, the sumo wrestler's weight would be represented on the y-axis, and the amount of time on the x-axis.
So the initial weight would occur at (0, 79.5) which is the positive y-intercept.
And since his weight is increasing at 5.5 kilograms per month, the slope of the linear function is positive.
Hence, the graph of the linear increasing function in quadrant 1 with a positive y-intercept.
Cheers.
Answer:64
Step-by-step explanation:
2*2*2*2=4*4=16. 16*16*16=4,096. 2*2*2*2*2*2=4*4*4=64. 4,096/64=64.
Answer:
79.24% probability that the average weight of rock and soil brought back by these rovers will be between 48 pounds and 52 pounds
We use the sampling distribution of the sample means of size 10 to solve this question, by the Central Limit Theorem. They are normally distributed with mean 50 and standard deviation 1.58.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
What is the probability that the average weight of rock and soil brought back by these rovers will be between 48 pounds and 52 pounds?
This is the pvalue of Z when X = 52 subtracted by the pvalue of Z when X = 48. So
X = 52
By the Central Limit Theorem
has a pvalue of 0.8962
X = 48
has a pvalue of 0.1038
0.8962 - 0.1038 = 0.7924
79.24% probability that the average weight of rock and soil brought back by these rovers will be between 48 pounds and 52 pounds
What sampling distribution should we use to compute this probability?
We use the sampling distribution of the sample means of size 10 to solve this question, by the Central Limit Theorem. They are normally distributed with mean 50 and standard deviation 1.58.