Answer:
True
Step-by-step explanation:
The given statement is true.
Area of a rectangle is length times width.
A rectangle with the side length of 4 and 5 inches would have an area of 20 square inches.
Hope this helps.
Answer:
False
Step-by-step explanation:
There can be two sets of side lengths 4, 5 inches and 2, 10 inches.
CAN SOMEONE PLEASE HELP
3rd time asking this question no one is helping right
Answer:
Component form : (-7 , 2)
Step-by-step explanation:
P(4 , 5) = P'(4 +x , 5+y) = P'(-3 , 7)
4 + x = -3
x = -3 - 4
x = -7
5 + y = 7
y = 7 - 5
y = 2
Vector form : -7i + 2j
Component form : (-7 , 2)
-9x - 3y = -15
Answer: (1,2)
Step-by-step explanation:
You must:
- Multiply the first equation by 3.
- Add both equations.
- Solve for the variable left. In this case will be x.
Then:
Substitute x=1 into any of the original equtions and solve for y:
The solution is: (1,2)
Answer:
The solution of the system of equation is (1 , 2)
Step-by-step explanation:
The system of equation is:
* 13x + y = 15 ⇒ (1)
* -9x - 3y = -15 ⇒ (2)
- By using elimination ⇒ we must make on of the
two variables in the two equations has the same value
with different sign
- So we will multiply equation (1) by 3 to eliminate y
∴ 3(13x) + 3(y) = 3(15)
∴ 39x + 3y = 45 ⇒ (3)
- Now add (2) and (3)
∴ 39x + -9x = 45 + -15
∴ 30x = 30 ⇒ ÷ 30 both sides
∴ x = 1
- Substitute the value of x in equation (1) or (2)
- Lets use (1)
∴ 13(1) + y = 15
∴ 13 + y = 15 ⇒ subtract 13 from both sides
∴ y = 15 - 13
∴ y = 2
∴ The solution of the system of equation is (1 , 2)
Answer:
domain { x : x ∈ R, x ≠ 6 }
Step-by-step explanation:
given
f(x) =
the denominator of f(x) cannot be zero as this would make f(x) undefined
Equating the denominator to zero and solving gives the value that x cannot be.
x - 6 = 0 ( add 6 to both sides )
x = 6 ← excluded value in the domain
domain is {x : x ∈ R, x ≠ 6 }
[ 6 0 2 -8
[7 -1 -11 4
[-9 -5 5 -10
b24 means the element of set B in the second row and 4th column.
(-8) is at that position.
The mathematical concept of well-defined groupings of objects, or sets, that are referred to as members or elements of the set. The only sets that are taken into consideration are those whose members are also sets because pure set theory only deals with sets.
Given that the set is,
B=[-4 10 -3 9
[ 6 0 2 -8
[7 -1 -11 4
[-9 -5 5 -10
B24 stands for the B element in the second row and fourth column.
There is a (-8) there.
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