PHYSICS HIGH SCHOOL

Two 100 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car B at –10 m/s when they collide head–on. If the resulting velocity of Car B after the collision is 8 m/s, what is the velocity of Car A after the collision?(I saw this question was asked previously, but the person did not provide the correct answer...)

Answers

Answer 1

Answer:

Answer:

$v_a = -10 m/s$

so car A will move with speed 10 m/s in opposite direction

Explanation:

As we know that when two cars collide then the momentum of two cars will remains conserved

so here we have

$P_i = P_f$

mass of two cars = 100 kg

speed of car A = 8 m/s

speed of car B = - 10 m/s

after collision the speed of car B = +8 m/s

now by momentum conservation equation

$m_1v_(1i) + m_2v_(2i) = m_1v_(1f) + m_2v_(2f)$

so we have

$100(8) + 100(-10) = 100(v_a) + 100(8)$

so we have

$v_a = -10 m/s$

so car A will move with speed 10 m/s in opposite direction

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Answers

The acceleration of an objection is directly proportional to the magnitude of the net force, in the same direction of the net force, and inversely proportional to the mass.

Hello there!

Explanation:

↓↓↓↓↓↓↓↓↓↓↓↓↓↓

Newton's second law of motion states that the total net force acting on an object is equal to mass times acceleration.

Newton's second law of motion formula:

↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓

F=force=newtons= $kg*(m)/(s^2)$

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For example:

↓↓↓↓↓↓↓↓↓↓↓

Calculate the force needed to accelerate an object to 4.3 m/s². The object has a mass of 2.2 kg. Round the answer to the nearest tenth.

↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓

A= 4.3 m/s²

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2.2 kg (4.3 m/s²)=9.46=9.5N

Answer⇒⇒⇒⇒⇒9.5N

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Answers

Answer:

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Answer:

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Explanation:

trust me bro

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Answers

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Answers

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Answers

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