b. Ivan Pavlov
c. Elizabeth Loftus
d. John Watson
Knowing the formula for water and table salt is an example of:_________________memory.
a. episodic
b. procedural
c. semantic
d. echoic
The part of the brain that appears to be involved in the processing of short-term memories into long term is the:
a. hypothalamus
b. hippocampus
c. corpus callosum
d. cerebrum
1. Mary Cover-Jones
2.Knowing the formula for water and table salt is an example of episodic memory. so d
3.Hippocampus
Answer:
1) Mary Cover-Jones
2) episodic
3) hippocampus
Hope this helped man!
B. moving with a constant speed
C. slowing down
D. maintaining a constant velocity
Answer:
Zero acceleration means velocity that's not changing.
Explanation:
The object be going at the bottom of the hill with velocity 7.75 m/s.
When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Given in the question a 400 kg object is sitting at rest at the top of a hill that is 30.0 m high and 80.0 m long measured along the hill . If there is no friction, velocity with which object be going at the bottom of the hill,
θ =sin^-1(30/80)
θ =22
F = 400 g sin(22) = 150 N
F = ma
150 = 400 a
a = 0.375 m/s²
v² - u²= 2 a s
v² - 0 = 2 x 0.375 x 80
v = 7.75 m/s
The object be going at the bottom of the hill with velocity 7.75 m/s.
To learn more about velocity refer the link:
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C.) They could not measure a change in stars' positions on the sky.
D.) They could not measure how big the Earth was.
The mass of the aluminum added is calculated through the principle of conservation of energy, specifically thermal energy. By considering the heat lost by the aluminum and gained by the water, we can rearrange the equation for heat transfer and find that the mass of the aluminum is approximately 37.9 grams.
In this physics question, we're looking at a thermodynamic process involving a chunk of aluminum and water. Given the known values of their respective specific heats, the mass of water, and their final equilibrium temperature, we're aiming to find the mass of the aluminum.
We begin by understanding that in a closed system, the heat gained by one body is equal to the heat lost by another. In this case, the aluminum is losing heat, and the water is gaining it. The equation for heat transfer (Q = mcΔT), where m is mass, c is specific heat, and ΔT is change in temperature.
The heat gained by the water = mass of water * specific heat of water * change of temperature in water = 200g * 4.18J/g°C * (18.9°C - 15.5°C) = 2836.4J.
This is equal to the heat lost by the aluminum. Solving the analogous heat equation for the mass of the aluminum gives us the answer:
m = Q / (c * ΔT) = 2836.4J / (0.897J/g°C * (91.4°C - 18.9°C)) = 37.9g
So the mass of the aluminum is approximately 37.9 grams.
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