a jar contains 65 pennies 27 nickels 30 dimes and 18 quarters a coin is randomly selected from the jar find each probability

Answers

Answer 1

Answer:

The required probabilities are $P(\text{pennies})=(13)/(28),P(\text{nickels})=(27)/(140),P(\text{dimes})=(3)/(14),P(\text{quarters})=(9)/(70)$ .

Given:

Pennies = 65

Nickels = 27

Dimes = 30

Quarters = 18

To find:

The probability of each.

Solution:

The probability formula:

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcomes}}$

Total number of coins:

$65+27+30+18=140$

The probability of selecting Pennies is:

$P(\text{pennies})=(65)/(140)$

$P(\text{pennies})=(13)/(28)$

The probability of selecting nickels is:

$P(\text{nickels})=(27)/(140)$

The probability of selecting dimes is:

$P(\text{dimes})=(30)/(140)$

$P(\text{dimes})=(3)/(14)$

The probability of selecting quarters is:

$P(\text{quarters})=(18)/(140)$

$P(\text{quarters})=(9)/(70)$

Therefore, the required probabilities are $P(\text{pennies})=(13)/(28),P(\text{nickels})=(27)/(140),P(\text{dimes})=(3)/(14),P(\text{quarters})=(9)/(70)$ .

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What multiplies to 378 and adds to -51

Answers

Your answer would be -9 & -42.

Here's why ...
(-9)*(-42) A negative times a negative equals a positive (378).
Now, -9-42=-51 & you add these because you have two negatives.

Hope this makes sense & helps you ! (:

Separate 185 into two parts so that one part is 31 more than the other part. Find each part.

Answers

9514 1404 393

Answer:

108, 77

Step-by-step explanation:

Let x represent the larger part. Then ...

x + (x -31) = 185

2x = 216

x = 108

x -31 = 77

The two parts are 108 and 77.

Find n.
6/9=n/36
n=_____

Answers

multiple 6 with 36 and divide with 9
n = 24

Answer:

its 24 Hope this have a great day!

Step-by-step explanation:

What is the sum of 5√7 and 3√28

Answers

$5 √(7)+3 √(28)=\n \n 5 √(7)+3*2 √(7)=\n \n 5 √(7)+6 √(7) =11 √(7)$

- Mariana debe tomar dos pastillas; una cada 6 horas y otra cada 9 horas. Si a cierta hora toma las dos pastillas juntas, ¿después de cuantas horas volverá a tomarlas simultáneamente?